Suppose a right triangle produces the following relationship for cot(0). Use this relationship to answer the questions. Note - the questions can be answered independently of each other. cot (8) (a) Express tan (0) in terms of A. You must use an upper case letter A. tan (0) (b) Express A in terms of cot(0). 6 - 6cot(0) cot (8) OA= OA= 6 A + 6 = OA 1-6cot(0) cot (0) OA = OA= cot (0) - 6 cot (0) 6cot (0) 1 cot (8) 6 - cot(0) cot (0)
Suppose a right triangle produces the following relationship for cot(0). Use this relationship to answer the questions. Note - the questions can be answered independently of each other. cot (8) (a) Express tan (0) in terms of A. You must use an upper case letter A. tan (0) (b) Express A in terms of cot(0). 6 - 6cot(0) cot (8) OA= OA= 6 A + 6 = OA 1-6cot(0) cot (0) OA = OA= cot (0) - 6 cot (0) 6cot (0) 1 cot (8) 6 - cot(0) cot (0)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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
Transcribed Image Text:Suppose a right triangle produces the following relationship for cot(0). Use this relationship to answer the questions.
Note - the questions can be answered independently of each other.
6
cot(8) = A + 6
(a) Express tan(0) in terms of A. You must use an upper case letter A.
tan (0)
(b) Express A in terms of cot(0) .
6 - 6cot(0)
cot(0)
A =
A =
A
O A
=
OA=
cot(0) - 6
cot (0)
1 - 6cot(0)
cot (0)
6cot(0) - 1
cot (8)
6- cot(0)
cot (8)
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