Suppose a researcher wants to estimate the difference in percentages of men and women who say they have used or expect to use televised home shopping. He wants a 95%confidence interval of width 0.08 or less.a. Approximately how many people should be included in the samples?b. Suppose the researcher wants to obtain individual estimates for the two percentages of interest. Will the sample size found in part a be large enough to provide estimates ofeach percentage correct to within 0.03 with probability equal to 0.99? Justify your response.a. The sample sizes should be n₁ = n₂ =(Round up to the nearest integer.)C

It is given that,The margin of error is 0.08The confidence level is 0.95. The objective is to find…

Answered: Suppose a researcher wants to estimate…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a survey, 28 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $45 and standard deviation of $14. Construct a confidence interval at a 99% confidence level. Give your answers to one decimal place. ________+________
4. on paper. random sample of 130 human body temperatures had a mean 98.25 degree and astandard deviation of 0.73 degree. Construct a 99% confidence interval for the average body temperature ofhealthy people.
Answer each question and justify all work for full You will need your z and t charts for this quiz. 1. Death penalty: A group claims that the overall feelings of the general population on the . death penalty is changing. 643 people were interviewed, and of them, 258 believed in using the death penalty. Construct a 95% confidence interval for the proportion of people that believe in the death penalty. Follow the steps below: What is the best point estimate for the proportion of people who believe in the death penalty? › (round to two decimal places)
You want to estimate the average difference in the number of complaints filed by women at work and the number of complaints filed by men at work. You took an SRS of 7 businesses and collected the following data for number of complaints in a year: men 1 3 2 4 6 3 5 women 8 7 6 3 5 12 15 Create a 90% confidence interval for the average difference in the number of complaints filed by women at work and the number of complaints filed by men at work (in a year). You must do this using table C. If this is a 2 sample interval, be sure to specify who is population 1 and who is population 2. If this is a matched pairs interval, be sure to state the order you subtracted your data. Once you create your interval, give a sentence explaining the meaning of the interval (what the numbers in the interval mean, NOT the meaning of 95%) in context of this problem. Round to any appropriate number of decimals.
A researcher wants to estimate the mean income of a population with a 95% confidence level and a margin of error of $100. How large should the sample size be for the estimation?
Next question If a sample proportion is 0.68, which of the following could be a 90% confidence interval for the population proportion? ..... Select all that apply. A. Lower bound: 0.59; Upper bound: 0.77 B. Lower bound: 0.66; Upper bound: 0.70 OC. Lower bound: 0.50; Upper bound: 0.77 D. Lower bound: 0.77; Upper bound: 0.95 E. Lower bound: 0.67; Upper bound: 0.71 F3 F4 F5 F7 F8 24 4. %23 2 3. 6. Left control option command
A survey of 32,782 adults in 2004 indicated that 24.6% of adults were current smokers. A similar study conducted in 1995 of 40,000 adults indicated that 29.7% were current smokers. a. Find and interpret a point estimate of the difference between the proportion of current smokers in 1995, and the proportion of current smokers in 2004. b. A 95% confidence interval for the true difference is (-0.058,-0.045). Interpret. c. What assumptions must you make for the confidence interval i part b to be valid? (…) a. Find a point estimate of the difference between the proportion of current smokers in 1995 and the proportion of current smokers in 2004. (Round to three decimal places as needed.)
a researcher wishes to develop an interval estimate for response scores on user surveys. She's not sure about the standard deviation, but in previous years the scores have ranged from 25 to 86. How large a sample should she draw if she wants to construct a 95% confidence interval level that will be within 3 points of the population mean score?
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