Suppose a random sample of size 54 is selected from a population with a = 11, Find the value of the standard error of the mean in each of thefollowing cases (use the finite population correction factor if appropriate).-a. The population size is infinite (to 2 decimals).b. The population size is N = 50,000 (to 2 decimals).inmC. The population size is N= 5000 (to 2 decimals).d. The population size is N= 500 (to 2 decimals).

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Answered: Suppose a random sample of size 54 is…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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22
Let a population consist of the values 7 cigarettes, 8 cigarettes, and 19 cigarettes smoked in a day. Show that when samples of size 2 are randomly selected with replacement, the samples have mean absolute deviations that do not center about the value of the mean absolute deviation of the population. What does this indicate about a sample mean absolute deviation being used as an estimator of the mean absolute deviation of a population? Calculate the mean absolute deviation for each possible sample of size 2 from the population. Sample Mean Absolute Deviation {7,7} {7,8} 0 0.5 6 {7,19} {8,7} 0.5 {8,8} 0 {8,19} 5.5 {19,7} 6 {19,8} 5.5 {19,19} 0 (Type integers or decimals rounded to one decimal place as needed.) Calculate the mean of the sample mean absolute deviations. The mean of the sample mean absolute deviations is (Type an integer or decimal rounded to one decimal place as needed.) 2 9
When asked: "What is the distribution of X ? X ~ N(___,___)." This notation is referring to N, a normal distribution, with the mean given in the first space and the standard deviation in the second space. Remember that the standard deviation of the sample means is different from the population standard deviation. The lengths of adult males' hands are normally distributed with mean 190 mm and standard deviation 7 mm. Suppose that 11 individuals are randomly chosen. Round final answers to 4 decimal places. a. What is the distribution of x? x N( b. For the group of 11, find the probability that the average hand length is more than 189. c. Find the first quartile for the average adult male hand length for this sample size. d. For part b), is the assumption that the distribution is normal necessary? Yes No
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Suppose heights, in inches, of male orangutans have an unknown distribution with mean 60 and standard deviation 3 inches. A sample of size n = 49 is randomly taken from the population and the mean is taken. Using the Central Limit Theorem for Means, what is the sample mean distribution?
Suppose that the City of Chicago is interested in potential revenues if they introduce a tolling station near O'Hare. Further suppose that the average time between cars is only 3.0 seconds; what is the average value of the distribution?
Use the central limit theorem to find the mean and standard error of the mean of the indicated sampling distribution. Then sketch a graph of the sampling distribution. The per capita consumption of red meat by people in a country in a recent year was normally distributed, with a mean of 113 pounds and a standard deviation of 37.7 pounds. Random samples of size 20 are drawn from this population and the mean of each sample is determined.
Use the Central Limit Theorem to find the mean and standard error of the mean of the sampling distribution. Then sketch a graph of the sampling distribution. The mean price of photo printers on a website is $227 with a standard deviation of $68. Random samples of size 21 are drawn from this population and the mean of each sample is determined.
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Use the central limit theorem to find the mean and standard error of the mean of the indicated sampling distribution. Then sketch a graph of the sampling distribution. The per capita consumption of red meat by people in a country in a recent year was normally distributed, with a mean of 111 pounds and a standard deviation of 37.8 pounds. Random samples of size 19 are drawn from this population and the mean of each sample is determined. 1₂ = 0 ...

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