Suppose a punch recipe calls for a given amount of orange soda, measured in ounces. int amount 32; We can compute the number of 12-ounce cans needed, assuming that the amount does not evenly divide into 12: int cans_needed amount / 12 + 1; Adjust the formula so that it also works for amounts that evenly divide into 12. And compute the number of ounces that are left over. For example, if 32 ounces are required, we need 3 cans and have 4 ounces left over. 1 #include 2 #include 3 4 using namespace std; 5 6 int main() 7 { 8 9 10 11 12 13 14 15 16 17 // Other values will be set during testing. // Your program needs to work with any amount. int amount 32; // Compute the number of cans needed and the ounces Left over // Your code goes here cout << "Cans needed: << cans_needed << endl; cout << "Ounces left over: " << left over << endl;

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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In city street grids, intersections are often defined by two integers, counting the position of horizontal and vertical streets
(sometimes called streets and avenues). Imagine traveling from position (h₁, ₁) to (h₂, v₂). How many blocks do you
traverse?
(h₂, v₂)
(h₁, v₂)
Even though there are many possible routes, the distance only depends on the differences h₂ h₁ and v₂ - ₁. However, you
need to take the absolute value because the differences might be negative.
Complete the following program that prints the number of blocks traveled, given the origin and destination of the trip (which will
change as your code is tested).
#include <<math>
3
4 using namespace std;
5
6 int main()
7 {
8
9
10
11
12
13
5555555
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int h1;
int v1;
int h2;
int v2;
cin >> h1;
cin >> v1;
cin >> h2;
cin >> v2;
/* Your code goes here */
cout << "Distance: << distance << endl;
Transcribed Image Text:In city street grids, intersections are often defined by two integers, counting the position of horizontal and vertical streets (sometimes called streets and avenues). Imagine traveling from position (h₁, ₁) to (h₂, v₂). How many blocks do you traverse? (h₂, v₂) (h₁, v₂) Even though there are many possible routes, the distance only depends on the differences h₂ h₁ and v₂ - ₁. However, you need to take the absolute value because the differences might be negative. Complete the following program that prints the number of blocks traveled, given the origin and destination of the trip (which will change as your code is tested). #include <<math> 3 4 using namespace std; 5 6 int main() 7 { 8 9 10 11 12 13 5555555 14 15 16 17 18 19 int h1; int v1; int h2; int v2; cin >> h1; cin >> v1; cin >> h2; cin >> v2; /* Your code goes here */ cout << "Distance: << distance << endl;
Suppose a punch recipe calls for a given amount of orange soda, measured in ounces.
int amount = 32;
We can compute the number of 12-ounce cans needed, assuming that the amount does not evenly divide into 12:
int cans_needed = amount / 12 + 1;
Adjust the formula so that it also works for amounts that evenly divide into 12. And compute the number of ounces that are left
over. For example, if 32 ounces are required, we need 3 cans and have 4 ounces left over.
1 #include <iostream>
2 #include <<math>
3
4 using namespace std;
5
6 int main()
7 {
8
9
10
11
12
13
14
15
16
17
// Other values will be set during testing.
// Your program needs to work with any amount.
int amount = 32;
// Compute the number of cans needed and the ounces left over
// Your code goes here
cout << "Cans needed: << cans_needed << endl;
cout << "Ounces left over: << left over << endl;
Transcribed Image Text:Suppose a punch recipe calls for a given amount of orange soda, measured in ounces. int amount = 32; We can compute the number of 12-ounce cans needed, assuming that the amount does not evenly divide into 12: int cans_needed = amount / 12 + 1; Adjust the formula so that it also works for amounts that evenly divide into 12. And compute the number of ounces that are left over. For example, if 32 ounces are required, we need 3 cans and have 4 ounces left over. 1 #include <iostream> 2 #include <<math> 3 4 using namespace std; 5 6 int main() 7 { 8 9 10 11 12 13 14 15 16 17 // Other values will be set during testing. // Your program needs to work with any amount. int amount = 32; // Compute the number of cans needed and the ounces left over // Your code goes here cout << "Cans needed: << cans_needed << endl; cout << "Ounces left over: << left over << endl;
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