Suppose a program P has the following three threads Threadi, Thread2, and Thread3, and a shared counter, count, as shown below: int count- 10; Semaphore Lock - 1; initial value is 1 Thread1(-) I do something Lock Waint(); count++; Lock Signal(); Thread2(.) do something Lock Wait: count Lock Signal() Thread3(-) I do something Lock Wain) printf "d", count): Lock Signal(). Upon the execution of the program P, the number of possible orders of execution of threads where the output will be 10 is Note : The above three threads are non preemptive threads.

Computer Networking: A Top-Down Approach (7th Edition)
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Author:James Kurose, Keith Ross
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Suppose a program P has the following three threads Thread1, Thread2, and
Thread3, and a shared counter, count, as shown below:
int count 10;
Semaphore Lock = 1; // initial value is I
Thread1(.)
Il do something
Lock. Wait():
count++;
Lock Signal();
Thread2(.)
Il do something
Lock. Wait();
count-;
Lock.Signal();
Thread3(.)
Il do something
Lock. Wait():
printf"id", count);
Lock.Signal():
Upon the execution of the program P, the number of possible orders of
execution of threads where the output will be 10 is
Note : The above three threads are non-preemptive threads.
Transcribed Image Text:Suppose a program P has the following three threads Thread1, Thread2, and Thread3, and a shared counter, count, as shown below: int count 10; Semaphore Lock = 1; // initial value is I Thread1(.) Il do something Lock. Wait(): count++; Lock Signal(); Thread2(.) Il do something Lock. Wait(); count-; Lock.Signal(); Thread3(.) Il do something Lock. Wait(): printf"id", count); Lock.Signal(): Upon the execution of the program P, the number of possible orders of execution of threads where the output will be 10 is Note : The above three threads are non-preemptive threads.
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