Suppose a professor want to test the hypothesis that average scores on a national quiz for morning (Class 1), afternoon (Class 2) and evening (Class 3) populations are equal. She wishes to test this at the 0.05 level. A random sample of quizzes is taken with the following results: Class 1 Class 2 Class 3 10 8 4 6. 10 8 1 Test, by hand, using ANOVA. 7966

Q: 3. √11

A:

Q: Find (+72+6) dz + C

A:

Q: -11sin (z)dz -

A:

Q: 4 Evaluate -1 0 5 by: 3 - 2 expanding along the first row expanding along the second column A A 1.…

A:

Q: రం్ియ 20 5-6 a06 5a 3. 3.

A:

Q: 10. (x² – 2y)³ 3

A: Given,          x2-2y3

Q: 4. 3*+4 72x-1

A:

Q: Find m2C and mZD. B. (3c - 17) (c+ 1) A

A:

Q: Max 3A + 2B IA+IB ≤ 10 3A +1B ≤ 24 1A + 2B ≤ 16 A, B 0

A:

Q: 6-7:

A: 6-7=-1

Q: Multiply. 3 x-4 3 3 2 X+4

A:

Q: Compute A B, where A = AB= -5 6 -5 0 and B = 6 7 2 9

A:

Q: 2.) 8(b+ 1) + 4 = 3(2b – 8) – 16

A: We can find the value of b in the following step

Q: a) : ?

A: here differentiate both sides with respect to x.

Q: to 2A+7 n-1

A:

Q: V16-x² B Evaluate S. Sezy2) (x²+y²) /16 –r²drdzde -

A: Given integral is, I=∫04∫016-x2∫x2+y24416-r2drdzdθ Now, integrating the given integral,…

Q: 4. Expand and simplify (2x + 3)*

A: We have to expand and simplify the following expression: . We will apply the binomial theorem to…

Q: 1x x*-5 =xp C O None of the other choices

A:

Q: 2070 = (16a + 10)15

A: 2070 = (16a+10)15 And (16e+11)17 =3723 To find  the values of a and e

Q: 9. (x² – 2)3

A:

Q: Simplify. [(21)4]² 1615 Enter your answer in the box.

A:

Q: Find Σ +i . Ο 30 Ο 31 Ο 32

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Q: 28 Σ

A:

Q: Fully simplify. (2/-54)(10/48)

A: The detailed solution is as follows below:

Q: |番,曲 1 dx (r-2)² 5. 2.

A: Given :

Q: (1+2 In æ)4 6.

A: topic - indefinite integral

Q: Evalvate S (4sin co) -8cos co) )do

A: Given that: ∫0π(4sinθ-8cosθ)dθ

Q: 29 Using the combination formula expand (5+x)

A:

Q: Prove that n² +n is divisible by 2, where n E N.

A:

Q: What is the least common multiple of 12 and 2? lcm (12,2)=(

A: Algebra

Q: 2r dr (1 - r)"

A:

Q: /2 2. 1/2

A: (a12+b12)(2a12-3b12)=2a12a12+2a12b12-3a12b12-3b12b12=2a+2a12b12-3a12b12-3b=2a-a12b12-3b