Suppose a population is known to be normally distributed with a mean, µ, equal to 116 and a standard deviation, o, equal to 14. Approximately what percent of the population would be between 116 and 130?

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Suppose a population is known to be normally distributed with a mean, μ, equal to 116 and a standard deviation, σ, equal to 14. Approximately what percent of the population would be between 116 and 130?

**Question: Normal Distribution Analysis**

Suppose a population is known to be normally distributed with a mean, \( \mu \), equal to 116 and a standard deviation, \( \sigma \), equal to 14. Approximately what percent of the population would be between 116 and 130?

**Answer Options:**

- 47.5%
- 81.5%
- 13.5%
- 95%
- 34%
- 68%

**Explanation:**

In a normal distribution, data falls symmetrically around the mean, creating a bell-shaped curve. The empirical rule (68-95-99.7 rule) is often used to estimate the data spread:

- **68%** of values fall within one standard deviation (\( \sigma \)) of the mean.
- **95%** fall within two standard deviations.
- **99.7%** fall within three standard deviations.

To find the percentage of the population between 116 and 130:
1. Calculate the number of standard deviations between 116 and 130. 
2. \( 130 - 116 = 14 \), which is one standard deviation from the mean.

Thus, approximately **34%** of the population is expected to be between the mean and one standard deviation above the mean (half of 68% because the distribution is symmetrical).
Transcribed Image Text:**Question: Normal Distribution Analysis** Suppose a population is known to be normally distributed with a mean, \( \mu \), equal to 116 and a standard deviation, \( \sigma \), equal to 14. Approximately what percent of the population would be between 116 and 130? **Answer Options:** - 47.5% - 81.5% - 13.5% - 95% - 34% - 68% **Explanation:** In a normal distribution, data falls symmetrically around the mean, creating a bell-shaped curve. The empirical rule (68-95-99.7 rule) is often used to estimate the data spread: - **68%** of values fall within one standard deviation (\( \sigma \)) of the mean. - **95%** fall within two standard deviations. - **99.7%** fall within three standard deviations. To find the percentage of the population between 116 and 130: 1. Calculate the number of standard deviations between 116 and 130. 2. \( 130 - 116 = 14 \), which is one standard deviation from the mean. Thus, approximately **34%** of the population is expected to be between the mean and one standard deviation above the mean (half of 68% because the distribution is symmetrical).
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