Suppose a population distribution has a mean of 86.1 and a a random sample of 83 observations from this population has a mean of 74.6. The sampling error of a is: 02.8 O-11.5 -27.7 22.5

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#5).
### Sampling Error Calculation Example

Suppose a population distribution has a mean of 86.1, and a random sample of 83 observations from this population has a mean of 74.6. The sampling error of \(\bar{x}\) is:

- ○ 2.8
- ○ -11.5
- ○ -27.7
- ○ 22.5

#### Explanation:

Sampling error represents the difference between the population mean and the sample mean. It is calculated as:

\[ \text{Sampling Error} = \text{Sample Mean} (\bar{x}) - \text{Population Mean} (\mu) \]

Given in the problem:
- Population Mean (\(\mu\)) = 86.1
- Sample Mean (\(\bar{x}\)) = 74.6

Calculate the sampling error:

\[ \text{Sampling Error} = 74.6 - 86.1 = -11.5 \]

Thus, the correct sampling error is -11.5.

#### Answer:
○ -11.5
Transcribed Image Text:### Sampling Error Calculation Example Suppose a population distribution has a mean of 86.1, and a random sample of 83 observations from this population has a mean of 74.6. The sampling error of \(\bar{x}\) is: - ○ 2.8 - ○ -11.5 - ○ -27.7 - ○ 22.5 #### Explanation: Sampling error represents the difference between the population mean and the sample mean. It is calculated as: \[ \text{Sampling Error} = \text{Sample Mean} (\bar{x}) - \text{Population Mean} (\mu) \] Given in the problem: - Population Mean (\(\mu\)) = 86.1 - Sample Mean (\(\bar{x}\)) = 74.6 Calculate the sampling error: \[ \text{Sampling Error} = 74.6 - 86.1 = -11.5 \] Thus, the correct sampling error is -11.5. #### Answer: ○ -11.5
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