Suppose a normally distributed set of data has a mean of 150 and a standard deviation of 17. Use the 68-95-99.7 rule to determine the percent of scores in the data set expected to be between the scores 116 and 167. You must draw a picture of the normal curve and shade the area you are

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### Understanding the Normal Distribution: Applying the 68-95-99.7 Rule

Suppose a normally distributed set of data has a mean of 150 and a standard deviation of 17. **Use the 68-95-99.7 rule to determine the percent of scores in the data set expected to be between the scores 116 and 167**.

To address this, keep in mind the following key points regarding the 68-95-99.7 Rule (Empirical Rule):
1. **68% of the data** falls within 1 standard deviation of the mean.
2. **95% of the data** falls within 2 standard deviations of the mean.
3. **99.7% of the data** falls within 3 standard deviations of the mean.

### Example Calculation:
- **Mean (\(\mu\))** = 150
- **Standard Deviation (\(\sigma\))** = 17

Using the formula \( \mu \pm n\sigma \):
- **1 standard deviation (\(\mu \pm \sigma\))**: \(150 \pm 17\) which gives (133, 167).
- **2 standard deviations (\(\mu \pm 2\sigma\))**: \(150 \pm 2 \times 17\) which gives (116, 184).
- **3 standard deviations (\(\mu \pm 3\sigma\))**: \(150 \pm 3 \times 17\) which gives (99, 201).

To find the percent of scores between 116 and 167:
- 116 is \(2\sigma\) below the mean: \(\mu - 2\sigma\) = \(150 - 34 = 116\)
- 167 is \(1\sigma\) above the mean: \(\mu + 1\sigma\) = \(150 + 17 = 167\)

**Conclusion:**
Using the 68-95-99.7 Rule:
- Between \(\mu - 2\sigma\) and \(\mu + \sigma\): which accounts for data from (116) to (167)
    - This range includes the following:
        - From \(\mu - 2\sigma\) to \(\mu\) = 95%/2 = 47.5%
        - From \(\mu\) to \(\mu + \sigma
Transcribed Image Text:### Understanding the Normal Distribution: Applying the 68-95-99.7 Rule Suppose a normally distributed set of data has a mean of 150 and a standard deviation of 17. **Use the 68-95-99.7 rule to determine the percent of scores in the data set expected to be between the scores 116 and 167**. To address this, keep in mind the following key points regarding the 68-95-99.7 Rule (Empirical Rule): 1. **68% of the data** falls within 1 standard deviation of the mean. 2. **95% of the data** falls within 2 standard deviations of the mean. 3. **99.7% of the data** falls within 3 standard deviations of the mean. ### Example Calculation: - **Mean (\(\mu\))** = 150 - **Standard Deviation (\(\sigma\))** = 17 Using the formula \( \mu \pm n\sigma \): - **1 standard deviation (\(\mu \pm \sigma\))**: \(150 \pm 17\) which gives (133, 167). - **2 standard deviations (\(\mu \pm 2\sigma\))**: \(150 \pm 2 \times 17\) which gives (116, 184). - **3 standard deviations (\(\mu \pm 3\sigma\))**: \(150 \pm 3 \times 17\) which gives (99, 201). To find the percent of scores between 116 and 167: - 116 is \(2\sigma\) below the mean: \(\mu - 2\sigma\) = \(150 - 34 = 116\) - 167 is \(1\sigma\) above the mean: \(\mu + 1\sigma\) = \(150 + 17 = 167\) **Conclusion:** Using the 68-95-99.7 Rule: - Between \(\mu - 2\sigma\) and \(\mu + \sigma\): which accounts for data from (116) to (167) - This range includes the following: - From \(\mu - 2\sigma\) to \(\mu\) = 95%/2 = 47.5% - From \(\mu\) to \(\mu + \sigma
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