Suppose a liver extract capable of carrying out normal metabolic reactions (including gluconeogenesis) is incubated with pyruvate partially labeled with deuterium at the methyl group (see below: D= deuterium, i.e., H-2) a) Explain why the oxaloacetate formed in step 1 of gluconeogenesis is only partially labeled (i.e., some of the oxaloacetate is labeled and some is not). b) Where would the label be found in glucose?

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