Suppose a data set is normally distributed with a mean u = 70 and the population standard deviation a 10. You want to find the cutoff value (x) for certain areas (p-values) of a normal distribution. Left area (p 0.09) In cell B3 type: =NORM.INV(0.09,70,10) Right area (p 0.09) In cell B4 type: =NORM.INV(0.91,70,10) Middle area (p%3D0.60) Using symmetry, the middle area of a normal curve has an area of p%-0.60, which leaves 1-0.60 0.40 for the two tails. Each tail will receive half of this number. The left tail will use p-0.20. The right tail will use 1-0.20 0.80. In cell B5 type: =NORM.INV(0.20,70,10) In cell C5 type: =NORM.INV(0.80,70,10) Complete cells B7 to B9 and C9 in the same manner.

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Suppose a data set is normally distributed with a mean u = 70 and
the population standard deviation a = 10.
You want to find the cutoff value (x) for certain areas (p-values) of a normal distribution.
Left area (p 0.09)
In cell B3 type: =NORM.INV(0.09,70,10)
Right area (p= 0.09)
In cell B4 type: =NORM.INV(0.91,70,10)
Middle area (P3D0.60)
Using symmetryY, the middle area of a normal curve has an area of p-0.60, which leaves
1-0.60= 0.40 for the two tails. Each tail will receive half of this number. The left tail will
use p-0.20. The right tail will use 1-0.20 = 0.80.
In cell B5 type: =NORM.INV(0.20,70,10)
In cell C5 type: =NORM.INV(0.80,70,10)
Complete.cels 87to 89 and C9 in the same manner
Transcribed Image Text:Suppose a data set is normally distributed with a mean u = 70 and the population standard deviation a = 10. You want to find the cutoff value (x) for certain areas (p-values) of a normal distribution. Left area (p 0.09) In cell B3 type: =NORM.INV(0.09,70,10) Right area (p= 0.09) In cell B4 type: =NORM.INV(0.91,70,10) Middle area (P3D0.60) Using symmetryY, the middle area of a normal curve has an area of p-0.60, which leaves 1-0.60= 0.40 for the two tails. Each tail will receive half of this number. The left tail will use p-0.20. The right tail will use 1-0.20 = 0.80. In cell B5 type: =NORM.INV(0.20,70,10) In cell C5 type: =NORM.INV(0.80,70,10) Complete.cels 87to 89 and C9 in the same manner
Left area of p30.39
Right area of p%3D0.24
Middle area of p-0.72
8.
12
9,
Transcribed Image Text:Left area of p30.39 Right area of p%3D0.24 Middle area of p-0.72 8. 12 9,
Expert Solution
Step 1

Assume, X be the normally distributed random variable with mean, μ=70 and standard deviation, σ=10.

The area under a normal curve is always 1. The cutoff x for "Left area (p=0.09)" will be the value of X, to the left of which the area under the normal curve (with μ=70 and σ=10.) is 0.09.

The cutoff x for "Right area (p=0.09)" will be the value of X, to the right of which the area under the normal curve (with μ=70 and σ=10.) is 0.09.

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