Suppose a curve is defined by the equation 16(x² + y²) = 45. Show that if you translate the curve to the right by units and down by units, then the new curve satisfies the equation %3D O a. 8z + 8y? - 12x- 24y =0 O b. 8z + 8y? - 12z +24y = 0 O c. 8r + 8y2 + 12z +24y = 0 O d. 8r - 8y? – 12z+24y= 0 %3D
Suppose a curve is defined by the equation 16(x² + y²) = 45. Show that if you translate the curve to the right by units and down by units, then the new curve satisfies the equation %3D O a. 8z + 8y? - 12x- 24y =0 O b. 8z + 8y? - 12z +24y = 0 O c. 8r + 8y2 + 12z +24y = 0 O d. 8r - 8y? – 12z+24y= 0 %3D
Chapter3: Graphs And Functions
Section3.3: Find The Equation Of A Line
Problem 3.62TI: Find an equation of a line perpendicular to the line y=12x3 that contains the point (6,4) .
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![Suppose a curve is defined by the equation 16(x² + y²) = 45. Show that if you translate the curve to the right by units
and down by units, then the new curve satisfies the equation
O a. 8x + 8y? – 12x- 24y =0
O b. 8z + 8y² – 12x +24y = 0
O c. 8z + 8y2 + 12z +24y = 0
O d. 8z - 8y? – 12z+ 24y = 0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F82ca3860-a6f5-4fb2-b8c0-36c3136849ee%2F37bcd35c-91e1-4a31-93ed-418d16e312f9%2Fnh46az_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Suppose a curve is defined by the equation 16(x² + y²) = 45. Show that if you translate the curve to the right by units
and down by units, then the new curve satisfies the equation
O a. 8x + 8y? – 12x- 24y =0
O b. 8z + 8y² – 12x +24y = 0
O c. 8z + 8y2 + 12z +24y = 0
O d. 8z - 8y? – 12z+ 24y = 0
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