Suppose a car approaches a hill and has an initial speed of 120 km/h at the bottom of the hill. The driver takes her foot off of the gas pedal and allows the car to coast up the hill. Note: the 790-kg car with an initial speed of 120 km/h is observed to coast up a hill and stops at a height 21 m above its starting point. a.) What is the magnitude of the average force of friction, in newtons, if the hill has a slope 2.7° above the horizontal?

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Suppose a car approaches a hill and has an initial speed of 120 km/h at the bottom of the hill. The driver takes her foot off of the gas pedal and allows the car to coast up the hill. Note: the 790-kg car with an initial speed of 120 km/h is observed to coast up a hill and stops at a height 21 m above its starting point.

a.) What is the magnitude of the average force of friction, in newtons, if the hill has a slope 2.7° above the horizontal? 

Expert Solution
Step 1: Given data

Mass of the vehicle is m equals 790 space kg

Initial speed is u equals 120 space km divided by straight h

Height at which the vehicle stops is h equals 21 space straight m

Slope of hill is theta equals 2.7 to the power of degree

Note:

1 space km equals 1000 space straight m

1 space straight h equals 60 space min.

1 space min. equals 60 space straight s

1 space straight N equals 1 space kg times straight m divided by straight s squared

1 space straight J equals 1 space Nm

Gravitational acceleration is g equals 9.8 space straight m divided by straight s squared

Find:

Magnitude of friction force.

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