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Suppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius ra has a charge of +Q, while the outer cylinder of radius rb has charge -Q. The electric field E at a radial distance r from the central axis is given by the function:

Suppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius ra has a charge of +Q, while the outer cylinder of radius rb has charge -Q. The electric field E at a radial distance r from the central axis is given by the function:

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Suppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius ra has a charge of +Q, while the outer cylinder of radius rb has charge -Q. The electric field E at a radial distance r from the central axis is given by the function:

Suppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius ra has a charge of +Q, while the outer cylinder of radius rh has charge -Q. srb The electric field E at a radial distance r from the central axis is given by the function: E = ge/d0 + B/r + bo where alpha (a)., beta (8), ao and bo are constants. Find an expression for its capacitance. First, let us derive the potential difference Voh between the two conductors. The potential difference is related to the electric field by: Edr = - Edr Calculating the antiderivative or indefinite integral, Vab = (-aageao + B + bo By definition, the capacitance Cis related to the charge and potential difference by: C = Evaluating with the upper and lower limits of integration for Vab, then simplifying: C = Q/( (e""b/ao - eTala0) + ß In ) + bo (
Transcribed Image Text:Suppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius ra has a charge of +Q, while the outer cylinder of radius rh has charge -Q. srb The electric field E at a radial distance r from the central axis is given by the function: E = ge/d0 + B/r + bo where alpha (a)., beta (8), ao and bo are constants. Find an expression for its capacitance. First, let us derive the potential difference Voh between the two conductors. The potential difference is related to the electric field by: Edr = - Edr Calculating the antiderivative or indefinite integral, Vab = (-aageao + B + bo By definition, the capacitance Cis related to the charge and potential difference by: C = Evaluating with the upper and lower limits of integration for Vab, then simplifying: C = Q/( (e""b/ao - eTala0) + ß In ) + bo (
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