Suppose a block of metal heated to 250°F and then brought into a room that is at 90 ° F at 5 pm. At 5:30 pm, the temperature difference between the metal block and the room is 5 ° F. If u is the temperature of the block of metal, what is the appropriate equation to describe the rate of change of temperature of the block? O du h (u-90) dt du %3D = hu dt O du =h (u- 250) | dt O du h (90 – u) dt
Suppose a block of metal heated to 250°F and then brought into a room that is at 90 ° F at 5 pm. At 5:30 pm, the temperature difference between the metal block and the room is 5 ° F. If u is the temperature of the block of metal, what is the appropriate equation to describe the rate of change of temperature of the block? O du h (u-90) dt du %3D = hu dt O du =h (u- 250) | dt O du h (90 – u) dt
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
16.
![Suppose a block of metal is heated to 250°F and then brought into a
room that is at 90 ° F at 5 pm. At 5:30 pm, the temperature difference
between the metal block and the room is 5 ° F. If u is the temperature
of the block of metal, what is the appropriate equation to describe the
rate of change of temperature of the block?
O du
%3D
h (u – 90)
dt
du
%3D
= hu
dt
O du
=h (u– 250)
-
dt
O du
h (90 – u)
dt](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc6901a79-ec70-418f-bd04-90b0c5cf940b%2Fe04861f4-a9a6-4f84-a1ef-dc7faaea4b59%2F7m6yibv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Suppose a block of metal is heated to 250°F and then brought into a
room that is at 90 ° F at 5 pm. At 5:30 pm, the temperature difference
between the metal block and the room is 5 ° F. If u is the temperature
of the block of metal, what is the appropriate equation to describe the
rate of change of temperature of the block?
O du
%3D
h (u – 90)
dt
du
%3D
= hu
dt
O du
=h (u– 250)
-
dt
O du
h (90 – u)
dt
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