Suppose a biology student is about to take an exam that is entirely multiple choice, where each question has 5 answer choices. This student only studied 60% of the material that is covered on this exam, so let us assume that there is a 60% chance that she knows the correct answer to any given question. If she does not know the answer, she will choose an answer at random. If the exam has a total of 40 questions on it, how many would you expect her to get wrong?

Q: メ+1

A:

Q: 10

A: To simplify 35+710.

Q: dactonive: 2. 2.

A: To factorise x2y2z2-16 ⇒x2y2z2-42 We know that a2-b2=a+ba-b Here a=xyz and b=4

Q: 8. 8. 3/ 2.

A:

Q: 40 -50-

A:

Q: b. N(0)

A: Given,  r→t=sint, t, cost                   ...1

Q: 5.1 #7

A: Given that                  A=60-1054-403-3502-425, λ=5

Q: Find lim (x,y)→(12,3) xy cos(x – 4y). OS 1. –36 2. 36 3. 3 4. 0

A:

Q: 31/2 / 1/2

A:

Q: 1 1 dx 3 5 x +x4

A:

Q: 1. 2. 3.

A:

Q: 2 3 B={ A= 3 Find: A+B .B+A .A-

A:

Q: 1.6+0.4(x+6)+3.2

A: To simplify the expression means writing it in the simplest form.

Q: 619 d. 4 10

A:

Q: 9/12+3/24

A:

Q: 198-33

A: Given: 198-33

Q: d 6

A: 5. In the given right triangle , the hypotenuse is 41 and the perpendicular length is 40. Apply the…

Q: expansion of (1-2m)“

A:

Q: 3. 18

A:

Q: 2. 27

A:

Q: 人 2. 2. 4

A: The given integral is ∫x24-x2dx. Let x=2 sin u. Then dx=2 cosu du. Apply the substitution and…

Q: 12 10 6. X%=

A:

Q: 1. 12

A: We can use the concept of Pythagoras theorem to solve the given problem.

Q: 1/20+1/10+1/4

A:

Q: 6-1 t.

A: