Suppose a 500. mL flask is filled with 0.90 mol of NO, and 0.20 mol of NO,. The following reaction becomes possible: NO, (g) + NO(g) = =2NO,(2) The equilibrium constant K for this reaction is 0.556 at the temperature of the flask. Calculate the equilibrium molarity of NO. Round your answer to two decimal places. OM

Suppose a 500. mL flask is filled with 0.90 mol of NO, and 0.20 mol of NO,. The following reaction becomes possible: NO, (g) + NO(g) = =2NO,(2) The equilibrium constant K for this reaction is 0.556 at the temperature of the flask. Calculate the equilibrium molarity of NO. Round your answer to two decimal places. OM

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Suppose a 500. mL flask is filled with 1.6 mol of N, and 0.10 mol of O,. The following reaction becomes possible: N,(g) +0,(g) 2NO(g) The equilibrium constant K for this reaction is 2.74 at the temperature of the flask. Calculate the equilibrium molarity of N,. Round your answer to two decimal places. 2:
O KINETICS AND EQUILIBRIUM 1/5 Calculating equilibrium composition from an equilibrium constant Suppose a 500. mL flask is filled with 1.1 mol of Cl,, 0.20 mol of HCl and 0.80 mol of CCl,. The following reaction becomes possible: Cl,(g) +CHCI, (g) = HCl(g)+CCl, (g) The equilibrium constant K for this reaction is 9.65 at the temperature of the flask. Calculate the equilibrium molarity of HCl. Round your answer to two decimal places. | M II
Calculating equilibrium composition from an equilibrium... 0/5 Suppose 500. mL flask is filled with 1.9 mol of H, and o0.50 mol of C1,. The following reaction becomes possible: H, (g) + Cl,(g) – 2HC1(g) The equilibrium constant K for this reaction is 3.61 at the temperature of the flask. Calculate the equilibrium molarity of H,. Round your answer to two decimal places. OM
Suppose a 500. mL flask is filled with 0.80 mol of H, and 0.90 mol of HI. The following reaction becomes possible: H, (g) +1,(g) – 2HI(g) The equilibrium constant K for this reaction is 3.50 at the temperature of the flask. Calculate the equilibrium molarity of I,. Round your answer to two decimal places. ?
Suppose a 500. mL flask is filled with 0.20 mol of Cl, and 1.5 mol of HCl. The following reaction becomes possible: H,(2) + Cl, (g) – 2HCI(3) The equilibrium constant K for this reaction is 0.754 at the temperature of the flask. Calculate the equilibrium molarity of Cl,. Round your answer to two decimal places. |M ?
Suppose a 500. mL flask is filled with 1.2 mol of CO, 2.0 mol of H,0 and 0.90 mol of CO,. The following reaction becomes possible: Co(2) + H,0(g) – Co,(3) +H,(g) The equilibrium constant K for this reaction is 0.545 at the temperature of the flask. Calculate the equilibrium molarity of H,0. Round your answer to two decimal places.
Suppose a 500. mlL flask is filled with 2.0 mol of NO,, 0.30 mol of CO and 1.3 mol of NO. The following reaction becomes possible: NO, (2) + CO(u) - NO()+co,@) The equilibrium constant K for this reaction is 6.41 at the temperature of the flask. Calculate the equilibrium molarity of NO. Round your answer to two decimal places.
Suppose a 500. mL flask is filled with 0.80 mol of NO, and 1.7 mol of NO. The following reaction becomes possible: NO, (g)+NO (g)2NO, (g) The equilibrium constant K for this reaction is 5.51 at the temperature of the flask. Calculate the equilibrium molarity of NO,. Round your answer to two decimal places. | M ?
Suppose a 250. mL flask is filled with 1.1 mol of NO,, 0.30 mol of CO and 1,3 mol of CO,. The following reaction becomes possible: NO, (g) +co(g) - NO(s)+Co,(g) The equilibrium constant K for this reaction is 7.86 at the temperature of the flask. Calculate the equilibrium molarity of CO. Round your answer to two decimal places.
Suppose a 250. mL flask is filled with 0.20 mol of N, and 0.10 mol of NO. The following reaction becomes possible: N,(2) +O,(g) – -2NO(g) The equilibrium constant K for this reaction is 9.83 at the temperature of the flask. Calculate the equilibrium molarity of N,. Round your answer to two decimal places.
O KINETICS AND EQUILIBRIUM Calculating equilibrium composition from an equilibrium constant Suppose a 500. mL flask is filled with 1.9 mol of NO,, 0.10 mol of N0 and 1.7 mol of CO,. The following reaction becomes possible: 2' NO,(g)+CO(g) -NO(g)+CO,(g The equilibrium constant K for this reaction is 4.70 at the temperature of the flask. Calculate the equilibrium molarity of NO. Round your answer to two decimal places. M TRADIS Explanation Check 2020 McGraw-Hill Education. All Rights Reserved. Terms of Use | Privacy | Acces NOV 242 PAGES étv 4 MacBook Air II
Suppose a 500. mL flask is filled with 0.70 mol of Cl,, 1.4 mol of CHCI, and 0.50 mol of CCl,. The following reaction becomes possible: 3 Cl,(g)+ CHC1,(g) – HC1 (g)+ CCl,(g) 4 The equilibrium constant K for this reaction is 1.78 at the temperature of the flask. Calculate the equilibrium molarity of HCl. Round your answer to two decimal places. ||M