Suppose a 250. mL flask is filled with 0.80 mol of H₂ and 0.90 mol of NH3. This reaction becomes possible: N₂(g) + 3H₂(g)2NH3 (8) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of N₂. You can leave out the M symbol for molarity. initial change equilibrium N₂ A x 0 H₂ 0 0 0 NH, 0 0 X
Suppose a 250. mL flask is filled with 0.80 mol of H₂ and 0.90 mol of NH3. This reaction becomes possible: N₂(g) + 3H₂(g)2NH3 (8) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of N₂. You can leave out the M symbol for molarity. initial change equilibrium N₂ A x 0 H₂ 0 0 0 NH, 0 0 X
Organic Chemistry
8th Edition
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Chapter23: Amines
Section23.5: Basicity
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Suppose a 250. mL flask is filled with 0.80 mol of H₂ and 0.90 mol of NH₂. This reaction becomes possible:
N₂(g) + 3H₂(g)2NH, (g)
Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the
equilibrium molarity of each compound after the reaction has come to equilibrium.
Use x to stand for the unknown change in the molarity of N₂. You can leave out the M symbol for molarity.
Explanation
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Expert Solution

Step 1
Molarity =moles/volume(in L)
Given, volume=250ml=0.250L
Moles of H2=0.80
Moles of NH3 =0.90
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