Heat CapacityWe define q, the amount of (energy transferred as) heat as directly proportional to the temperature change (AT):q-CATwhere C is a positive constant (called the heat capacity of the sample). We can see from this equation that the larger the temperature change is(for a given sample), the more heat must have been transferred. If AT-1° C, then q and C are numerically equal; thus, heat capacity canbe defined as the amount of heat needed to cause a temperature change of 1 : °CBy convention AT is calculated by subtracting the initial temperature from the final temperature.AT = Tfinal - Tinitiat%3DTherefore, for a sample that warmed up, the algebraic sign of ATis positive • and the algebraic sign of q is positiveFor a samplethat cooled down, the algebraic sign AT is negative and the algebraic sign of q is negativeIf the temperature of a sample decreased from 20.00°C to 18.00°C, then (in degrees Celsius) isAT - 18,00 : "c- 20.00 : °C = 2.00 : CIn Kelvin,AT -( 18.00 • + 273.15) K-( 20.00 • + 273.15) K- 2.00 • KNotice that AT is the same in "C and K because the 273.15 that we add to the Celsius reading to convert to K cancels out when we subtract. Suppose 400.0 ) of heat transfer causes a sample's temperature to drop by 2.00°C. Calculate the heat capacity.AT=The algebraic signs are bothAs far as this sample is concerned, the process isthe direction of heat flow is• the sample.We can rearrange the equation q= CAT to solve for C:C=AT• /KNote that the value of Cis the same whether we use J/C or J/K; we can also write the units as Jc or J K.Need help? Watch this.http://youtu.be/Lqb21L181w

Answered: Image /qna-images/answer/fe4d04fc-37b8-4786-a671-0af87dcb287b.jpg

Suppose 400.0 ) of heat transfer causes a sample's temperature to drop by 2.00°C. Calculate the heat capacity. AT= The algebraic signs are both As far as this sample is concerned, the process is the direction of heat flow is • the sample. We can rearrange the equation q= CAT to solve for C: C= AT • /K Note that the value of Cis the same whether we use J/C or J/K; we can also write the units as Jc or J K. Need help? Watch this. https://youtu.be/Lqb21Lt8 1w

Suppose 400.0 ) of heat transfer causes a sample's temperature to drop by 2.00°C. Calculate the heat capacity. AT= The algebraic signs are both As far as this sample is concerned, the process is the direction of heat flow is • the sample. We can rearrange the equation q= CAT to solve for C: C= AT • /K Note that the value of Cis the same whether we use J/C or J/K; we can also write the units as Jc or J K. Need help? Watch this. https://youtu.be/Lqb21Lt8 1w

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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