Suppose ℙ(?1|?2)=0.46 P ( E 1 | E 2 ) = 0.46 , ℙ(?2|?1)=0.92 P ( E 2 | E 1 ) = 0.92 , and ℙ(?1)×ℙ(?2)= P ( E 1 ) × P ( E 2 ) = 0.14. Determine ℙ(?2) P ( E 2 ) , giving your answer correct to two decimal places.
Suppose ℙ(?1|?2)=0.46 P ( E 1 | E 2 ) = 0.46 , ℙ(?2|?1)=0.92 P ( E 2 | E 1 ) = 0.92 , and ℙ(?1)×ℙ(?2)= P ( E 1 ) × P ( E 2 ) = 0.14. Determine ℙ(?2) P ( E 2 ) , giving your answer correct to two decimal places.
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Question
Suppose ℙ(?1|?2)=0.46
P
(
E
1
|
E
2
)
=
0.46
, ℙ(?2|?1)=0.92
P
(
E
2
|
E
1
)
=
0.92
, and ℙ(?1)×ℙ(?2)=
P
(
E
1
)
×
P
(
E
2
)
=
0.14. Determine ℙ(?2)
P
(
E
2
)
, giving your answer correct to two decimal places.
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