Suppose 10% of students are veterans and 131 students are involved in sports. How unusual would it be to have no more than 16 veterans involved in sports? (16 veterans is about 12.21%) When working with samples of size 131, what is the mean of the sampling distribution for the proportion of veterans? When working with'samples of size 131, what is the standard error of the sampling distribution for the proportion of veterans? Compute P(p < 0.1221). P(p < 0.1221) = NOTE: Give results accurate to 4 decimal places. Is this result unusual? O Yes, there is a less than 50% chance of this happening by random variation. O No, there is at least a 50% chance of this happening by random variation.

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Suppose 10% of students are veterans and 131 students are involved in sports. How unusual would it be to
have no more than 16 veterans involved in sports? (16 veterans is about 12.21%)
When working with samples of size 131, what is the mean of the sampling distribution for the proportion of
veterans?
When working with'samples of size 131, what is the standard error of the sampling distribution for the
proportion of veterans?
Compute P(p < 0.1221).
P(p < 0.1221) =
NOTE: Give reşults accurate to 4 decimal places.
Is this result unusual?
O Yes, there is a less than 50% chance of this happening by random variation.
O No, there is at least a 50% chance of this happening by random variation.
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Transcribed Image Text:Suppose 10% of students are veterans and 131 students are involved in sports. How unusual would it be to have no more than 16 veterans involved in sports? (16 veterans is about 12.21%) When working with samples of size 131, what is the mean of the sampling distribution for the proportion of veterans? When working with'samples of size 131, what is the standard error of the sampling distribution for the proportion of veterans? Compute P(p < 0.1221). P(p < 0.1221) = NOTE: Give reşults accurate to 4 decimal places. Is this result unusual? O Yes, there is a less than 50% chance of this happening by random variation. O No, there is at least a 50% chance of this happening by random variation. Submit Question
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