Suppose 1.67 C of charge passes through the filament of a light bulb in 2.00 seconds. How many electrons pass through the filament in 5.00 s? Express all numerical values in three significant figures. The current in the light bulb is:

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Suppose 1.67 C of charge passes through the filament of a light bulb in 2.00 seconds. How many electrons pass through the filament in 5.00 s? Express all numerical values in three significant figures.

The current in the light bulb is:

Suppose 1.67 Cof charge passes through the filament of a light bulb in 2.00 seconds. How many electrons pass through the filament in 5.00 s? Express oll numericol values in three significant figures.
The current in the light bulb is:
milliamperes
The total amount of charge passing through the filament in t-5.00 s is:
Q =
coulombs
Since a single electron has a charge of -1.60 x 1019 C, the number of electrons passing through the filament in t-5.00 s is:
N-
x 1019 electrons
Transcribed Image Text:Suppose 1.67 Cof charge passes through the filament of a light bulb in 2.00 seconds. How many electrons pass through the filament in 5.00 s? Express oll numericol values in three significant figures. The current in the light bulb is: milliamperes The total amount of charge passing through the filament in t-5.00 s is: Q = coulombs Since a single electron has a charge of -1.60 x 1019 C, the number of electrons passing through the filament in t-5.00 s is: N- x 1019 electrons
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