Supply the missing quantities. Outcome P(An E) = P(An F) = P(BNG) = P(BH) = = 0.2 0.1 Figure A B U 0.5 0.8 Description E F G H I J P(In C) = 0.14 P(Jn C) = 0.56

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Finite Math - Conditional Probability & Independence

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Supply the missing quantities.
Outcome
P(An E) =
P(An F)
P(BNG) =
=
P(BH) =
=
0.2
0.1
Figure
A
B
0.5
0.8
Description
E
F
G
H
I
J
P(In C) = 0.14
P(Jn C) = 0.56
Transcribed Image Text:Supply the missing quantities. Outcome P(An E) = P(An F) P(BNG) = = P(BH) = = 0.2 0.1 Figure A B 0.5 0.8 Description E F G H I J P(In C) = 0.14 P(Jn C) = 0.56
Figure
Description
A tree diagram has two stages. Stage 1 has three nodes and stage 2 has six nodes.
• In stage 1, the branch from the starting position to node A is labeled 0.2. The branch from the
starting position to node B is labeled 0.1. The branch from the starting position to node C is
an answer blank.
• In stage 2, the branch from node A to node E is an answer blank. The branch from node A to
node F is labeled 0.5.
• In stage 2, the branch from node B to node G is an answer blank. The branch from node B to
node H is labeled 0.8.
• In stage 2, the branch from node C to node I is an answer blank. The branch from node C to
node J is an answer blank.
Node I is labeled P(In C) = 0.14.
• Node J is labeled P(Jn C) = 0.56.
Transcribed Image Text:Figure Description A tree diagram has two stages. Stage 1 has three nodes and stage 2 has six nodes. • In stage 1, the branch from the starting position to node A is labeled 0.2. The branch from the starting position to node B is labeled 0.1. The branch from the starting position to node C is an answer blank. • In stage 2, the branch from node A to node E is an answer blank. The branch from node A to node F is labeled 0.5. • In stage 2, the branch from node B to node G is an answer blank. The branch from node B to node H is labeled 0.8. • In stage 2, the branch from node C to node I is an answer blank. The branch from node C to node J is an answer blank. Node I is labeled P(In C) = 0.14. • Node J is labeled P(Jn C) = 0.56.
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