Supply a reason for each step in the solution below showing ((p→ q) → plp is a tautology. [(p - q) - p] → p = [(p q) → p] V p = -[~(p q) V p] v p = -[~(~p v q) V p] v p = [(~p v q) A~p] V p = [mp^(~p v q)] vp Step 1 Step 2 Step 3 Step 4 Step 5 Step 6 Step 7 = ~p Vp Thererefore, [(p → q) p] p is a tautology.
Supply a reason for each step in the solution below showing ((p→ q) → plp is a tautology. [(p - q) - p] → p = [(p q) → p] V p = -[~(p q) V p] v p = -[~(~p v q) V p] v p = [(~p v q) A~p] V p = [mp^(~p v q)] vp Step 1 Step 2 Step 3 Step 4 Step 5 Step 6 Step 7 = ~p Vp Thererefore, [(p → q) p] p is a tautology.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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State if the following step are:
- Negation Law
- De Morgan's Law
- Disjunctive form
- Absorption law
- Cummutative Law
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