supervisor O b. O d. SELECT Efname as Efname. E.kdate as Ebdate FROM Employee E WHERE E.bdate < ALL (select Sabdate. from Employee s where E.super ssn. < S.Ssn); SELECT Efname as Efname, E.bdate as Ebdate FROM Employee E JOIN EMPLOYEES ON E.Super 5.5 WHERE E.bdate <$,bdate; SELECT Efname as Efnane, E.bdate as Ebdate FROM Employee F WHERE > ALL (select Subulate from where Employee S super 550, < 5.550); SELECT Efname as Efnane, Ebdate as Ebdate FROM Employee C 30IN CMPLOYEES ON EAURAC_0 WHERE Ebate (select from where date Employee s super..san. = S.Ssn);

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
Given the following Employee table schema:
Employee(ssn:string, fname: string, Iname: string, bdate: date, super ssn:string.
salary.real, dno:integer);
Which one of the below given queries "Finds the employees who are older than their
supervisor
Ob
Ос
O d.
SELECT Efname as Efname. Ekdate as Ebdate
FROM Employee E
WHERE E.bdate < ALL (select Sabdate.
from
Employee s
where E.super_ssn. < S.ssn);
SELECT Efname as Efname, E.bdate as Ebdate
FROM Employee E JOIN EMPLOYEES ON ESUper 550-5.550.
WHERE E.bdate < $.bdate;
SELECT Efname as Efnane, E.bdate as Ebdate
FROM Employee E
WHERE > ALL (select Subulate
from Employee s
where super 550 5.550);
SELECT Efname as Efnane, E.bdate as Ebdate
FROM Employee C 30IN CMPLOYEES ON EUR -0
WHERE date <dates
O SELECT Efname as Efname, Ebdate as Ebdate
from Employee C
WHERE .kdate> (select Subdats
Employee S
from
where E.super_ssn= S.Ssn);
Transcribed Image Text:Given the following Employee table schema: Employee(ssn:string, fname: string, Iname: string, bdate: date, super ssn:string. salary.real, dno:integer); Which one of the below given queries "Finds the employees who are older than their supervisor Ob Ос O d. SELECT Efname as Efname. Ekdate as Ebdate FROM Employee E WHERE E.bdate < ALL (select Sabdate. from Employee s where E.super_ssn. < S.ssn); SELECT Efname as Efname, E.bdate as Ebdate FROM Employee E JOIN EMPLOYEES ON ESUper 550-5.550. WHERE E.bdate < $.bdate; SELECT Efname as Efnane, E.bdate as Ebdate FROM Employee E WHERE > ALL (select Subulate from Employee s where super 550 5.550); SELECT Efname as Efnane, E.bdate as Ebdate FROM Employee C 30IN CMPLOYEES ON EUR -0 WHERE date <dates O SELECT Efname as Efname, Ebdate as Ebdate from Employee C WHERE .kdate> (select Subdats Employee S from where E.super_ssn= S.Ssn);
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