= 16 W/m.K. The inner diameter and thickness of the pipe are 26 cm and 1 cn espectively. The surrounding temperature is 28 °C. The convective heat transfe oefficient at the steam side and the outside of the pipe is 90 W/m?.K and 1 N/m².K, respectively. Derive an expression for the temperature profile across th ipe thickness as a function of the radial position r.
= 16 W/m.K. The inner diameter and thickness of the pipe are 26 cm and 1 cn espectively. The surrounding temperature is 28 °C. The convective heat transfe oefficient at the steam side and the outside of the pipe is 90 W/m?.K and 1 N/m².K, respectively. Derive an expression for the temperature profile across th ipe thickness as a function of the radial position r.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
![Superheated steam at 350 °C flows through a pipe whose thermal conductivity is
kp = 16 W/m.K. The inner diameter and thickness of the pipe are 26 cm and 1 cm,
respectively. The surrounding temperature is 28 °C. The convective heat transfer
coefficient at the steam side and the outside of the pipe is 90 W/m?.K and 15
W/m?.K, respectively. Derive an expression for the temperature profile across the
%3D
pipe thickness as a function of the radial position r.
T = 28 °C, h, = 15 W/m?.K
Ts = 350 °C
h; = 90 W/m?.K
ri
%3D
r2
Cross-sectional view
of the pipe](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F76305403-f421-4312-9b46-528ddd78d416%2F780ec5b4-e9b9-47e6-a096-e4504b1dede6%2Fnhy5fm_processed.png&w=3840&q=75)
Transcribed Image Text:Superheated steam at 350 °C flows through a pipe whose thermal conductivity is
kp = 16 W/m.K. The inner diameter and thickness of the pipe are 26 cm and 1 cm,
respectively. The surrounding temperature is 28 °C. The convective heat transfer
coefficient at the steam side and the outside of the pipe is 90 W/m?.K and 15
W/m?.K, respectively. Derive an expression for the temperature profile across the
%3D
pipe thickness as a function of the radial position r.
T = 28 °C, h, = 15 W/m?.K
Ts = 350 °C
h; = 90 W/m?.K
ri
%3D
r2
Cross-sectional view
of the pipe
Expert Solution
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Step 1
Boundary Conditions
T( r1 ) = T1 =350oC
T( r2 ) = T2 = 28oC
T(r) = C1 lnr + C2
T( r1 ) = C1 lnr1 + C2
T( r2 ) = C1 lnr2 + C2
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