= 16 W/m.K. The inner diameter and thickness of the pipe are 26 cm and 1 cn espectively. The surrounding temperature is 28 °C. The convective heat transfe oefficient at the steam side and the outside of the pipe is 90 W/m?.K and 1 N/m².K, respectively. Derive an expression for the temperature profile across th ipe thickness as a function of the radial position r.

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Superheated steam at 350 °C flows through a pipe whose thermal conductivity is
kp = 16 W/m.K. The inner diameter and thickness of the pipe are 26 cm and 1 cm,
respectively. The surrounding temperature is 28 °C. The convective heat transfer
coefficient at the steam side and the outside of the pipe is 90 W/m?.K and 15
W/m?.K, respectively. Derive an expression for the temperature profile across the
%3D
pipe thickness as a function of the radial position r.
T = 28 °C, h, = 15 W/m?.K
Ts = 350 °C
h; = 90 W/m?.K
ri
%3D
r2
Cross-sectional view
of the pipe
Transcribed Image Text:Superheated steam at 350 °C flows through a pipe whose thermal conductivity is kp = 16 W/m.K. The inner diameter and thickness of the pipe are 26 cm and 1 cm, respectively. The surrounding temperature is 28 °C. The convective heat transfer coefficient at the steam side and the outside of the pipe is 90 W/m?.K and 15 W/m?.K, respectively. Derive an expression for the temperature profile across the %3D pipe thickness as a function of the radial position r. T = 28 °C, h, = 15 W/m?.K Ts = 350 °C h; = 90 W/m?.K ri %3D r2 Cross-sectional view of the pipe
Expert Solution
Step 1

Mechanical Engineering homework question answer, step 1, image 1

 

Boundary Conditions

T( r1 ) = T1 =350oC

T( r2 ) = T2 = 28oC

dTdr=C1r

T(r) = C1 lnr + C2

T( r1 ) = C1 lnr1 + C2

T( r2 ) = C1 lnr2 + C2

 

Mechanical Engineering homework question answer, step 1, image 2

 

Mechanical Engineering homework question answer, step 1, image 3

 

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