sup EOD f(ξ) - f(—ξ) |_ sup\f(x) = f(w)| 2,w€OD
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Let the expression on the right-hand side of this inequality represents the diameter of the image of a holomorphic function f from the unit disc to the complex plane, with z, w, and zeta on the boundary of D. What I don't understand is what happens to the zeta2 in the denominator on the left-hand side? Isn't it less than 1, and so dividing by a number less than 1 make the fraction larger? I don't see how the inequality holds. What is happening to the zeta2 portion?

Transcribed Image Text:**Mathematical Inequality in Analysis**
This equation presents an important concept in mathematical analysis involving the supremum (sup). The concept revolves around the properties of functions on the boundary of the unit disk (denoted by ∂
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