Sunday 4 10 Monday 24 20 Tuesday 21 20 Wednesday 18 20 Thursday 22 20 Friday 28 20 Saturd Observed Expected Components 10 3.6 0.8 0.05 0.2 0.2 3.2 4.9 Based upon the follow-up analysis, why was the null hypothesis rejected? O Although births are less likely on the weekends, births are more than twice as likely during the week. O Although births are less likely on the weekdays, births are more than twice as likely during the weekend. O The doctor was off track. She should have hypothesized that births are equally likely for all days of the week. O The doctor was off track. She should have hypothesized that babies are twice as likely to be born on a weekend (Saturday and Sunday) than on a weekday (Monday through Friday).

Q: 3 -4- -0- 4. 2.

A:

Q: 3y² - 2y-1 (-)-5y²- 2y +6

A:

Q: 7+3.5-11

A: Let's Solve,

Q: 5(18)

A: To find5(18)

Q: 2 3 3 4 6 8

A: The mean is computed below.   Aptitude score(x) Frequency(f) x*f 0 4 0 1 2 2 2 3 6 3 0 0…

Q: 2) 36³x=¹

A:

Q: expand (a-b)7

A: The solution is given in the next step.

Q: 4root2*4root2

A:

Q: 7,20

A:

Q: +–3m+–9m+4+5+–10m

A: The expression is given as 1+–3m+–9m+4+5+–10m. Simplifying the given expression. 1+–3m+–9m+4+5+–10m…

Q: 4. Expand and simplify (2x + 3)*

A: We have to expand and simplify the following expression: . We will apply the binomial theorem to…

Q: 4(5+6)=

A: Given: 4(5+6)=

Q: Expand (a −b)4

A:

Q: d. 1 3a+18 = 1 - 8 a+6

A:

Q: (n + 4)3 =

A: Given query is to expand (n+4)3

Q: limx→- f(x) limo+ f(x) limx→ = = =

A:

Q: 18(9+7)+3

A: 18(9+7)+3