i only need part c. please do it correct. # 13.3 Practice: Analysis of Variance (ANOVA) ## Given Data:- **Sum of Squares, Treatment**: \( 653.3 \)- **Sum of Squares, Error**: \( 66 \)- **Mean Squares, Treatment**: \( 326.6 \)- **Mean Squares, Error**: \( 5.5 \)### Task a) Calculate the value of the test statistic (to 2 decimals):\[ F_{\text{Statistic}} = 59.38 \]- **p-value**: less than \( 0.01 \)### Conclusion:Based on the given p-value, the conclusion is:**Conclude that not all treatment means are equal**.### Task b) Calculate the value of Fisher's LSD (to 2 decimals):\[ \text{Fisher's LSD} = 3.23 \]Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, and treatments B and C. Use \( \alpha = 0.05 \).#### Difference Analysis Table:| Difference | Absolute Value | Conclusion ||--------------------------|----------------|-----------------------|| \( \overline{x}_A - \overline{x}_B \) | 16 | Significant difference || \( \overline{x}_A - \overline{x}_C \) | 6 | Significant difference || \( \overline{x}_B - \overline{x}_C \) | 10 | Significant difference |### Task c) Use Fisher's LSD procedure to develop a 95% confidence interval estimate of the difference between the means of treatments A and B (to 2 decimals). Enter negative values as negative numbers.\[ \text{95% Confidence Interval} = [-21.23, -11.77] \]The confidence interval indicates that the difference between the means of treatments A and B is significantly different and falls within the range of \(-21.23\) to \(-11.77\). This practice exercise demonstrates the application of the Analysis of Variance (ANOVA) and Fisher's Least Significant Difference (LSD) procedure in determining the significance of differences between treatment means. ### 13.3 Practice#### Exercise:The following data are from a completely randomized design.| | Treatment A | Treatment B | Treatment C ||---------------|-------------|-------------|-------------|| Observations | 32 | 45 | 33 || | 30 | 44 | 36 || | 30 | 45 | 35 || | 26 | 47 | 36 || | 32 | 49 | 40 |- Sample mean: | 30 | 46 | 36 |- Sample variance: | 6.00 | 4.00 | 6.50 | a. At the α = 0.05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal?Compute the values below (to 1 decimal, if necessary).- **Sum of Squares, Treatment:** 653.3 ✔️- **Sum of Squares, Error:** 66 ✔️- **Mean Squares, Treatment:** 326.6 ✔️- **Mean Squares, Error:** 5.5 ✔️Calculate the value of the test statistic (to 2 decimals).- **Test Statistic (F-value):** 59.38 ✔️The **p-value** is: - **Less than 0.01** ✔️What is your conclusion?- **Conclusion:** Reject the null hypothesis and conclude that not all treatment means are equal. ✔️b. Calculate the value of Fisher's LSD (to 2 decimals).- **Fisher's LSD:** 2.39 ✔️

Answered: Image /qna-images/answer/d06245b6-4e65-4c5b-b568-4c555f6e15e3.jpg

Sum of Squares, Error Mean Squares, Treatment Difference Absolute Value Mean Squares, Error Calculate the value of the test statistic (to 2 decimals). 59.38 TA-TB The p-value is less than 0.01 What is your conclusion? Conclude that not all treatment means are equal b. Calculate the value of Fisher's LSD (to 2 decimals). 3.23 Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, and treatment FA-FC 16 66 10 326.6 -11.77 5.5 Hide Feedback Partially Correct Conclusion FB-FC Significant difference c. Use Fisher's LSD procedure to develop a 95% confidence interval estimate of the difference between the means of treatments A and B (to 2 decimals). E numbers. -21.23 Significant difference Significant difference

Sum of Squares, Error Mean Squares, Treatment Difference Absolute Value Mean Squares, Error Calculate the value of the test statistic (to 2 decimals). 59.38 TA-TB The p-value is less than 0.01 What is your conclusion? Conclude that not all treatment means are equal b. Calculate the value of Fisher's LSD (to 2 decimals). 3.23 Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, and treatment FA-FC 16 66 10 326.6 -11.77 5.5 Hide Feedback Partially Correct Conclusion FB-FC Significant difference c. Use Fisher's LSD procedure to develop a 95% confidence interval estimate of the difference between the means of treatments A and B (to 2 decimals). E numbers. -21.23 Significant difference Significant difference

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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