sulation sta 22. Refer to Exhibit 4. The expected value of x (expected mean) for the sample is a 0.18 b. 9 C. 8 d. 121 23. Refer to Exchibit 4. The standard error of the mean for the sample is a 0.5000 b. 0.1800 c. 0.0208 d. 0.0164
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- The systolic blood pressure (BP) of adults in the USA is nearly normally distributed with a mean of 120 and standard deviation of 23 .Someone qualifies as having Stage 2 high blood pressure if their systolic blood pressure is 160 or higher.(a) Around what percentage of adults in the USA have stage 2 high blood pressure? Give your answer rounded to two decimal places.________%(b) Stage 1 high BP is specified as systolic BP between 140 and 160. What percentage of adults in the US qualify for stage 1? Give your answer rounded to **two decimal places**. _____%(c) Your doctor tells you that you are in the 30th percentile (e.g. bottom 30%) for blood pressure among US adults. What is your systolic BP? Give your answer rounded to *two decimal places*. ________mmHg Thank you.A random variable is not normally distributed, but it is mound shaped. It has a mean of 18 and a standard deviation of 2. For a sample of size 13, state the mean of the sample mean and the standard deviation of the sample mean. Round to two decimal places if necessary.μx̄ = σx̄ =Measuring lung function: One of the measurements used to determine the health of a person's lungs is the amount of air a person can exhale under force in one second. This is called forced expiratory volume in one second, and is abbreviated FEV₁. Assume the mean FEV₁ for 10-year-old boys is 2.1 liters and that the population standard deviation is 6=0.5. A random sample of 58 10-year- old boys who live in a community with high levels of ozone pollution are found to have a sample mean FEV₁ of 1.98 liters. Can you conclude that the mean FEV₁ in the high-pollution community differs from 2.1 liters? Use the α=0.10 level of significance and the P-value method with the TI-84 calculator. Part 1 of 4 State the appropriate null and alternate hypotheses. Ho: μ = 2.1 H₁:μ #2.1 This hypothesis test is a two-tailed Part: 1 / 4 Part 2 of 4 test. Find the P-value. Round the answer to at least four decimal places. P-value:
- Ages of Gamblers The mean age of a sample of 20 people who were playing the slot machines is 48.5 years, and the standard deviation is 6.8 years. The mean age of a sample of 31 people who were playing roulette is 54 with a standard deviation of 3.2 years. Can it be concluded at α=0.10 that the mean age of those playing the slot machines is less than those playing roulette? Use μ1 for the mean age of those playing slot machines. Assume the variables are normally distributed and the variances are unequal. (a)State the hypotheses and identify the claim with the correct hypothesis. H0: claim/not claim H1: claim/not claim This hypothesis test is a one-tailed/two tailed. P-value: = (b)Find the critical value(s). Round the answer(s) to two decimal places. If there is more than one critical value, separate them with commas. Critical value(s): (c)Compute the test value. Round the intermediate calculations to at least three decimal places and final answer to two decimal places. z=…You want to obtain a sample to estimate a population mean. Based on previous evidence, you believe the population standard deviation is approximately σ=68.8. You would like to be 98% confident that your estimate is within 3 of the true population mean. How large of a sample size is required? Do not round mid-calculation. n=The amount of trash generated by US households (in lbs per day) is normally distributed. You take a sample of 10 people. The sample average is xbar=10.91 lbs, and the sample standard deviation is s=4.736. What is the 99% Conf. Int. for the mean? Group of answer choices a. 6.04 to 15.78 b. 8.33 to 13.49 c. 8.09 to 13.73 d. 7.74 to 14.08
- Ages of Gamblers The mean age of a sample of 22 people who were playing the slot machines is 51.1 years, and the standard deviation is 6.8 years. The mean age of a sample of 34 people who were playing roulette is 54.2 with a standard deviation of 3.2 years. Can it be concluded at a = 0.01 that the mean age of those playing the slot machines is less than those playing roulette? Use µ, for the mean age of those playing slot machines. Assume the variables are normally distributed and the variances are unequal. Part 1of hypoth Pa Part 2 of 5 Find the critical value(s). Round the answer(s) to at least three decimal places. If there is more than one critical value, separate them with commas. Critical value(s):A normal distribution has mean u = 63 and standard deviation o =20. Find and interpret the z-score for x=57.An unknown distribution has a mean of 100, a standard deviation of 100, and a sample size of 100. Let X = one object of interest. What is the mean of EX? (Enter an exact number as an integer, fraction, or decimal.) 1000 X How are the population mean and sample size used to calculate the mean of sums? Additional Materials
- Measuring lung function: One of the measurements used to determine the health of a person's lungs is the amount of air a person can exhale under force in one second. This is called forced expiratory volume in one second, and is abbreviated FEV1. Assume the mean FEV1 for 10 -year-old boys is 2.1 liters and that the population standard deviation is =σ0.4 . A random sample of 35 10 -year-old boys who live in a community with high levels of ozone pollution are found to have a sample mean FEV1 of 1.98 liters. Can you conclude that the mean FEV1 in the high-pollution community differs from 2.1 liters? Use the =α0.10 level of significance and the P -value method with the TI-84 calculator. Part: 0 / 4 0 of 4 Parts Complete Part 1 of 4 State the appropriate null and alternate hypotheses. :H0 :H1 This hypothesis test is a ▼(Choose one) test.Accordi the historical data, the life expectancy in Mexico is equal to the life expectancy in Spain. A new study has been made to see whether this has changea. Records of 205 individuals from Mexico who died recently are selected at random. The 205 individuals lived an average of 71.8 years with a standard deviation of 2.6 years. Records of 250 individuals from Spain who died recently are selected at random and independently. The 250 individuals lived an average of 71.2 years with a standard deviation of 3.0 years. Assume that the population standard deviation of the life expectancy can be estimated by the sample standard deviations, since the samples that are used to compute them are quite large. At the 0.05 level of significance, is there enough evidence to support the claim that the life expectancy, H1, in Mexico is not equal to the life expectancy, µ,, in Spain anymore? Perform a two-tailed test. Then complete the parts below. Carry your intermediate computations to at least three…The lengths of pregnancies in a small rural village are normally distributed with a mean of 270.2 days and a standard deviation of 17.8 days.In what range would you expect to find the middle 98% of most pregnancies? Between_______ and__________ .Enter your answers as numbers. Your answers should be accurate to 1 decimal places.
