Suggest two methods to reduce or dissipate the heat in the ferromagnetic core.
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A: The req answer is given below.
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Suggest two methods to reduce or dissipate the heat in the ferromagnetic core.
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- Two atoms of the same substance, one singly ionized and the other triply ionized, are eachaccelerated from rest through same potential difference. The ions enter the same uniformmagnetic field at 90 degrees. Derive an expression fora) their velocity (V2/ V1) entering the field. b) their radii (r2/ r1) of curvature in the field.A solenoid with 4 x 107 turns/m has an iron core placed in it whose magnetic susceptibility is 4.0 × 103 . (a) If a current of 2.0 A flows through the solenoid, what is the magnetic field in the iron core? (b) What is the effective surface current formed by the aligned atomic current loops in the iron core? (c) What is the self-inductance of the filled solenoid?For a solenoid in vacuum of length l = 10 cm with 104 turns per meter calculate the current required to create the field B= 70 μT. Provide your answer in SI units.
- It is desired to construct a solenoid that will have a resistance of 5.30 Ω (at 20°C) and produce a magnetic field of 4.00 ✕ 10−2 T at its center when it carries a current of 3.40 A. The solenoid is to be constructed from copper wire having a diameter of 0.500 mm. If the radius of the solenoid is to be 1.00 cm, determine the following. (The resistivity of copper at 20°C is 1.7 ✕ 10−8 Ω · m.) (a) the number of turns of wire needed to build the solenoid (b) the length the solenoid should have, in cm.Consider the RL direct current circuit shown. The circuit contains R = 4.0 Ω, L = 10 mH, & ε = 12 V. The circuit is charging. (a) Determine the time constant for the circuit? (b) What is the maximum current in the circuit? (c) What is the current one time constant (t = τ )? (d) When the current is 0.5 A, what is the strength of the magnetic field in the solenoid, with n = N/ℓ = 319x103 turns/m. ( T×m/A)Consider a long, closely wound solenoid with 10,000 turns per meter. What current, in amperes, is needed in the solenoid to produce a magnetic field inside the solenoid, near its center, that is 104 times the Earth’s magnetic field of 4.8 × 10-5 T?
- Calculate the energy associated with the magnetic field of a 175-turn solenoid in which a current of 2.25 A produces a magnetic flux of 3.81 x 10-4 T · m2 in each turn.It is desired to construct a solenoid that will have a resistance of 5.60 N (at 20°C) and produce a magnetic field of 4.00 X 10¬2T at its center when it carries a current of 3.10 A. The solenoid is to be constructed from copper wire having a diameter of 0.500 mm. If the radius of the solenoid is to be 1.00 cm, determine the following. (The resistivity of copper at 20°C is 1.7 × 10-8 0· m.) (a) the number of turns of wire needed to build the solenoid 1029 v turns (b) the length the solenoid should have X cm 1.034*10**7It is desired to construct a solenoid that will have a resistance of 4.15 2 (at 20°C) and produce a magnetic field of 4.00 x 10-2 T at its center when it carries a current of 5.00 A. The solenoid is to be constructed from copper wire having a diameter of 0.500 mm. If the radius of the solenoid is to be 1.00 cm, determine the following. (The resistivity of copper at 20°C is 1.7 x 10-8 0 • m.) (a) the number of turns of wire needed to build the solenoid turns (b) the length the solenoid should have cm