Sucrose is a chiral compound and enantio-pure sucrose has specific rotation [?]D20 = +66.5°. A sample of synthesized sucrose from the organic chemistry lab was tested, and the specific rotation of the sample is [?]D20= +60.1°.a) determine the enantiomeric excess (ee) of the sample.b) calculate the ratio of two enantiomersc) draw the structure of the minor enantiomer in the sample. ### Structure of (+)-SucroseThe image above depicts the chemical structure of the disaccharide sugar molecule known as (+)-sucrose. Sucrose is composed of two monosaccharides: glucose and fructose.#### Detailed Description:1. **Glucose Unit**: - The glucose part of sucrose is shown on the left side. - It has a six-membered ring structure, known as a pyranose form. - The hydroxyl groups (OH) are attached to specific carbon atoms, and the CH₂OH group is located at the top, indicating the orientation of the glucose unit.2. **Fructose Unit**: - The fructose component is depicted on the right side. - It has a five-membered ring structure, known as a furanose form. - Similar to glucose, it contains hydroxyl groups (OH) attached to various carbon atoms, with a CH₂OH moiety positioned at the three o'clock position.3. **Glycosidic Bond**: - The glucose and fructose units are connected by an oxygen atom bridging their respective rings. - This bond is specifically a glycosidic linkage, formed between the anomeric carbon of the glucose and the carbon of the fructose, signifying a condensation reaction.Understanding this structure is essential for appreciating how sucrose functions biologically and why it is widely used as a sweetener.

Sucrose is a chiral compound, and enantio-pure sucrose has specific rotation [α]D 20 = +66.5°. A sample of synthesized sucrose from the organic chemistry lab was tested, and the specific rotation of the sample is [α]D 20 = +60.1°.(a) The enantiomeric excess (ee) of the sample can be given as :(b) Now, Major enantiomer = (+) enantiomer : Minor enantiomer = (-) enantiomer : The ratio of the two enantiomer can be given as : Major : Minor = 95.185 : 4.815⇒19.7 : 1 (c) The structure of the minor enantiomer in the sample is given below :