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Substitution in the Indefinite Integral Part 1. Using the substitution: u = =x* + 10. Re-write the indefinite integral then evaluate in terms of u. S-9z*a* + 10)" dz = /O-1 Note: answer should be in terms of u only Part 2. Back substituting in the antiderivative you found in Part 1. above we have |-92(2* + 10) " dz =|

Substitution in the Indefinite Integral Part 1. Using the substitution: u = =x* + 10. Re-write the indefinite integral then evaluate in terms of u. S-9z*a* + 10)" dz = /O-1 Note: answer should be in terms of u only Part 2. Back substituting in the antiderivative you found in Part 1. above we have |-92(2* + 10) " dz =|

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Substitution in the Indefinite Integral Part 1. Using the substitution: u = x* + 10. Re-write the indefinite integral then evaluate in terms of u. J-90%a* + 10)" da = I-I Note: answer should be in terms of u only Part 2. Back substituting in the antiderivative you found in Part 1. above we have |-9z(2* + 10) " dz =| Note: answer should be in terms of x only
Transcribed Image Text:Substitution in the Indefinite Integral Part 1. Using the substitution: u = x* + 10. Re-write the indefinite integral then evaluate in terms of u. J-90%a* + 10)" da = I-I Note: answer should be in terms of u only Part 2. Back substituting in the antiderivative you found in Part 1. above we have |-9z(2* + 10) " dz =| Note: answer should be in terms of x only
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