Substituting this simplified numerator back into the limit, factoring and canceling common factors, we have 3t+ 3 3a + 3 f'(a) = lim t+6 t-a = lim a + 6 t-a - 15t 15a ta (t+6)(a + 6)(t - a) = lim x ta (t+6)(a + 6) Substituting this simplified numerator back into the limit, factoring and canceling common factors, we have 3t+ 3 3a + 3 f'(a) = lim t+6 t-a = lim a + 6 t-a - 15t 15a ta (t+6)(a + 6)(t - a) = lim x ta (t+6)(a + 6)
Substituting this simplified numerator back into the limit, factoring and canceling common factors, we have 3t+ 3 3a + 3 f'(a) = lim t+6 t-a = lim a + 6 t-a - 15t 15a ta (t+6)(a + 6)(t - a) = lim x ta (t+6)(a + 6) Substituting this simplified numerator back into the limit, factoring and canceling common factors, we have 3t+ 3 3a + 3 f'(a) = lim t+6 t-a = lim a + 6 t-a - 15t 15a ta (t+6)(a + 6)(t - a) = lim x ta (t+6)(a + 6)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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