Substitute s, = 2 into the function f(t) = -4.9t2 + vot + Sp. f(t) = -4.9t2 + vot + 2v When the object is at the given maximum height we have -4.9t2 + vat = 388 V 388 Step 3 Now, differentiate v f(t) with respect to t , to obtain the velocity v(t) as a function of time t, v(t) = t + Vo: When the object reaches the topmost point, it comes to rest (before starting to fall down). Hence, it's velocity, v(t), at that point of time is m/sec. Substitute this value for v(t) in the expression for v(t) and simplify to obtaint in terms of vo- Vo Submit Skip (you cannot come back)