Subpart 1: Newton's Second Law along the y-axis (i) Write Newton's Second Law along the y-axis by adding all forces in the y-direction taking into account their signs (forces pointing upwards are positive and downward are negative) in terms of the normal force N, weight mg, F and 8. In both scenarios, there is no acceleration along the y-direction, therefore, a, = 0. ZF,= -Fsine+N-mg (ii) Using (1) to solve for N. N= mg + Fsin(25°) (2) Think: In (2) is N greater than the weight, less than the weight or equal to the weight? = may = 0 (1) Subpart 2: Set up Newton's Second Law in the x-direction when the ice block is stationary. (i) Write Newton's Second Law along the x-axis by adding all forces in the x-direction taking into accountr their signs (forces pointing to the right are positive and pointing to the left are negative) when the block is not moving in terms of F, 0, and the force of static friction f. DON'T forget the subscript on fg. If the block is not moving, then ax = 0. ΣFx= = (ii) What value of static friction should you use just before the block starts moving? fs.max Ο με Ν = max = 0 (3)

Subpart 1: Newton's Second Law along the y-axis (i) Write Newton's Second Law along the y-axis by adding all forces in the y-direction taking into account their signs (forces pointing upwards are positive and downward are negative) in terms of the normal force N, weight mg, F and 8. In both scenarios, there is no acceleration along the y-direction, therefore, a, = 0. ZF,= -Fsine+N-mg (ii) Using (1) to solve for N. N= mg + Fsin(25°) (2) Think: In (2) is N greater than the weight, less than the weight or equal to the weight? = may = 0 (1) Subpart 2: Set up Newton's Second Law in the x-direction when the ice block is stationary. (i) Write Newton's Second Law along the x-axis by adding all forces in the x-direction taking into accountr their signs (forces pointing to the right are positive and pointing to the left are negative) when the block is not moving in terms of F, 0, and the force of static friction f. DON'T forget the subscript on fg. If the block is not moving, then ax = 0. ΣFx= = (ii) What value of static friction should you use just before the block starts moving? fs.max Ο με Ν = max = 0 (3)

Name: The FBD of the block should have looked like this.1. Drag and drop th
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Description: The FBD of the block should have looked like this.1. Drag and drop the heads and tails of the vectorsto construct the free-body diagram.2. Note that angles do not need to be exact andmagnitudes are not considered.ffric; 180°N; 90°mg; 271°F: 335°1.A

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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