Subnetting the address space 172.16.0.0/16 to provide at least 80 host addresses per subnet. List the first 3 subnets, host ranges, and broadcast. Make a table for the list.
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- SUBNET ADDRESSING Consider the router and the two attached subnets below (A and B). The number of hosts is also shown below. The subnets share the 23 high-order bits of the address space: 144.145.110.0/23 : A 175 hosts QUESTION 2 OF 10 Answer How many hosts can there be in this address space? 144.145.110.0/23 B Assign subnet addresses to each of the subnets (A and B) so that the amount of address space assigned is minimal, and at the same time leaving the largest possible contiguous address space available for assignment if a new subnet were to be added. Then answer the questions below. 84 hostsSUBNET ADDRESSING Consider the router and the two attached subnets below (A and B). The number of hosts is also shown below. The subnets share the 23 high-order bits of the address space: 144.145.110.0/23 175 hosts QUESTION 3 OF 10 A Answer What is the subnet address of subnet A? (CIDR notation) 144,145.110.0/23 Assign subnet addresses to each of the subnets (A and B) so that the amount of address space assigned is minimal, and at the same time leaving the largest possible contiguous address space available for assignment if a new subnet were to be added. Then answer the questions below. B 84 hosts• IPV6 addresses use 128 bits to represent an address which includes bits to be used for subnetting. The second half of the address (least significant 64 bits) is always used for hosts only. Therefore, there is no compromise if we subnet the network. Use the Figure below to Create five subnets using route prefix 2001:db:acad::/48 (1 Marks) Routing Prefix Subnet ID Interface ID 48 Bits 16 Bits 64 Bits
- Network Address 172.85.26.0/23 Chippendale LAN 12 Hosts Chippendale Ultimo LAN Glebe LAN 45 Hosts 85 Hosts Ultimo City Glebe City/Glebe LAN 210 Hosts Given the following information and diagram and the IP address 172.85.26.0/23, use VLSM addressing to assign IP addresses for different subnets. Complete the Table with the Network Address and Host Address for different LANS. All host addresses will be the 8th host address in each subnet. Complete the Table with IP address using 'xxx.xxx.XXx.Xxx' without prefix. For example: 192.168.10.15 for IP address rather than 192.168.10.15/24. Host Network Network Address Host Address Requirement 45 Ultimo LAN 12 Chippendale LAN 210 City/Glebe LAN 85 Glebe LANRefer to the exhibit. There are 3 LAN networks in the diagram. The network address given is 192.168.1.0/24. Your task is to do subnetting to support 62 hosts for each network.=) Listen With at least 14 subnets, 14 hosts, and a network address of 192.10.10.0, find default class, subnet mask, total number of valid hosts and subnets, and number of bits borrowed. Write your answer with steps and calculations.
- show the complete soluSubnetting (Subnetting) Fill in the blanks. (If possible show your solution) Number of needed usable hosts: 45Network Address : 220.100.100.0Address class : Default subnet mask :Costum subnet mask :Total number of subnets :Total number of host addresses :Number of usable addresses :Number of bits borrowed : What is the 5th subnet range? :What is the subnet number for the 4th subnet? :What is the subnet broadcast address for 13th subnet? :What are the assignable addresses for the 12th subnet? :Refer the exhibit and the required number of hosts given. Subnet the address 192.168.50.0/24 for the required number of hosts using VLSM and complete the subnet table using the following instructions: NW: 192.168.50.0/24 NET-X: 45 USABLE HOSTS NET-Z: 2 USABLE HOSTS NET-Y: 25 USABLE HOSTS ------ GO/O R2 G0/0 GO/1 GO/1 R1 PC2 PC1 Assign the first subnet to network with the highest host requirement. Assign the second subnet to the network with the second highest host requirement. Assign the third subnet to the network with the third highest host requirement. Subnet Table: Subnet No. of Subnet First Last Usable Broadcast Subnet Name Usable Address Usable Host Address Mask hosts Host Address required Address
- An organization is granted a block of addresses with the beginning address 14.24.74.0/24. The organization needs to have 5 subnets as shown below: 3 subnets ,each with 64 address 2 subnets ,each with 32 address8. Design 8 subnets for a company with the site address 201.75.38.0. a) What is the network mask? b) What is the subnet mask? c) How many hosts (addresses) can be supported on each subnet? d) What is the address of the 5th subnet?Refer to the following exhibit. R1(config)# aaa new-model R1 (config)# R1(config)# radius server Server-R R1(config-radius-server)# address ipv4 192.168.1.101 auth-port 1812 acct-port 1813 R1(config-radius-server) R1(config-radius-server) R1(config)# # key RADIUS-Pa55w0rd #exit Explain the reason(s) of specifying the ports being used for RADIUS and the key in the configuration. How could you include the RADIUS server as a AAA server?