## Submission (1)### Convert the following pseudo code into assembly code. (‘//’ represents comments)```plaintextarray1 13h, 14h, 15h, 16h // Each element is 1 byte longarray2 12h, 13h, 14h, 15h // Each element is 1 byte longlength1 = number of items in Array1. // length1 is a symbolic constantlength2 = number of items in Array2. // length2 is a symbolic constantsample1 = 30h // This variable is 1 byte long initialized with 30sample2 = 5h // This variable is 1 byte longmaxlength = max of length1 and length2. // maxlength is 1 byte long variableindex = 0. // This is a variable initialized with 0While ( index < maxlength ) { If (array1[index] > array2[index]) exp1 = (array1[index] * sample1) / (array2[index] * sample2) // Only store the quotient of the division in exp1 and exp1 is a 16-bit long variable else exp1 = 0 index = index + 1}```This pseudo code involves initializing arrays and constants, then iterating through the arrays with a loop. Depending on the comparison of elements, it performs a calculation and stores results conditionally. **Submission (2)**- **array1** elements are **1 byte** long- **array2** elements are **1 byte** long- **length1** and **length2** are symbolic constants- **sample1** and **sample2** are **1 byte** long variables initialized with 30h, and 5h respectively- **maxlength** is a **1 byte** long variable and uninitialized in the beginning - Inside the code section, compute the largest between **length1** and **length2** and store it in **maxlength**- **Index** is a variable that is **1 byte** long and initialized with 0- **Exp1** is a variable that is **2 byte** long- You are free to use any register and user-defined temporary memory variables to store the values- Your code must produce correct results- Also handle corner cases (e.g., if the divisor is zero, assign 0 to **exp1**)

Name: ## Submission (1)### Convert the following pseudo code into assembly
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Description: ## Submission (1)### Convert the following pseudo code into assembly code. (‘//’ represents comments)```plaintextarray1 13h, 14h, 15h, 16h // Each element is 1 byte longarray2 12h, 13h, 14h, 15h // Each element is 1 byte longlength1 = number

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Submission (1) Convert the following pseudo code into assembly code. ( 7/' represents comments) // Each element is 1 Byte long arrayl 13h, 14h, 15h, 16h array2 12h, 13h, 14h, 15h // Each element is 1 Byte long // lengthl is a Symbolic constant // length2 is a Symbolic constant // this variable is 1 byte long initialized with 30 lengthl = number of items in Arrayl. length2 = number of items in Array2 samplel = 30h sample2 = 5h. // this variable is 1 byte long maxlength = max of lengthl and length2. // maxlength is // this is a variable initialized with 0 1 byte long variable index = 0. index < maxlength ) { If (arrayl [index] > array2 [index] expl = (arrayl[index] * samplel) / (array2 [index] only store the quotient of the division in exp1 and exp1 is 7716 bit long variable While ( Sample2) else expl index = index + 1 = 0

Submission (1) Convert the following pseudo code into assembly code. ( 7/' represents comments) // Each element is 1 Byte long arrayl 13h, 14h, 15h, 16h array2 12h, 13h, 14h, 15h // Each element is 1 Byte long // lengthl is a Symbolic constant // length2 is a Symbolic constant // this variable is 1 byte long initialized with 30 lengthl = number of items in Arrayl. length2 = number of items in Array2 samplel = 30h sample2 = 5h. // this variable is 1 byte long maxlength = max of lengthl and length2. // maxlength is // this is a variable initialized with 0 1 byte long variable index = 0. index < maxlength ) { If (arrayl [index] > array2 [index] expl = (arrayl[index] * samplel) / (array2 [index] only store the quotient of the division in exp1 and exp1 is 7716 bit long variable While ( Sample2) else expl index = index + 1 = 0

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Question

## Submission (1)

### Convert the following pseudo code into assembly code. (‘//’ represents comments)

```plaintext
array1 13h, 14h, 15h, 16h // Each element is 1 byte long
array2 12h, 13h, 14h, 15h // Each element is 1 byte long

length1 = number of items in Array1. // length1 is a symbolic constant
length2 = number of items in Array2. // length2 is a symbolic constant

sample1 = 30h // This variable is 1 byte long initialized with 30
sample2 = 5h // This variable is 1 byte long

maxlength = max of length1 and length2. // maxlength is 1 byte long variable

index = 0. // This is a variable initialized with 0

While ( index < maxlength ) {
If (array1[index] > array2[index])
exp1 = (array1[index] * sample1) / (array2[index] * sample2)
// Only store the quotient of the division in exp1 and exp1 is a 16-bit long variable
else
exp1 = 0

index = index + 1
}
```

This pseudo code involves initializing arrays and constants, then iterating through the arrays with a loop. Depending on the comparison of elements, it performs a calculation and stores results conditionally.

**Submission (2)**

- **array1** elements are **1 byte** long
- **array2** elements are **1 byte** long
- **length1** and **length2** are symbolic constants
- **sample1** and **sample2** are **1 byte** long variables initialized with 30h, and 5h respectively
- **maxlength** is a **1 byte** long variable and uninitialized in the beginning
- Inside the code section, compute the largest between **length1** and **length2** and store it in **maxlength**
- **Index** is a variable that is **1 byte** long and initialized with 0
- **Exp1** is a variable that is **2 byte** long
- You are free to use any register and user-defined temporary memory variables to store the values
- Your code must produce correct results
- Also handle corner cases (e.g., if the divisor is zero, assign 0 to **exp1**)

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