The following data was obtained on a study regarding low carb diet and a high protein diet. The results of each group are displayed in the table, and the sample meanrepresents the average weight lost. Construct a 99% confidence interval for the mean weight lost of the low carb diet minus the mean weight lost from the high protein diet.Select all answers that are true.StudySample meanSample standarddeviationSample sizeLow carb5.5230High Protein4.5330(-.814,2.814)(-.346, 2.436)(-.999,2.999)The confidence interval can be use to test the alternative hypothesis that the mean weight lost from the low carb is not equal to the mean weight lost from the highprotein diet. Based on the 99% confidence interval we would fail to reject the null hypothesis that the mean weight lost is equal for each diet.(-0.762,2.762)The degrees of freedom for the t-distribution is 50The degrees of freedom for the t-distribution is 510000 00

The sample mean and sample standard deviation for low carb and high protein are given.Want to…

Answered: Study The following data was obtained…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The EPA tests cars for city miles per gallon (mpg). For one model, a sample of 16 cars were tested for mpg, the results follow. 28 25.7 25.8 28 28.5 29.8 30.2 30.4 26.9 28.3 29.8 27.2 26.7 27.7 29.5 28 Find the 95% confidence interval for mean mpg. Find the 99% confidence interval for mean mpg.
Report an appropriate hypothesis test for a positive linear relationship and use a 5% significance level. Explain the potential error in words, in context. In the answer options below I have used the phrase “a certain relationship” because I don’t want to give away exactly what type of relationship it is. Group of answer choices We would be accepting that there was a certain relationship between Sale amount and Tip when actually there wasn’t. We would not be accepting that there was a certain relationship between Sale amount and Tip when indeed there wasn’t. We would not be accepting that there was a certain relationship between Sale amount and Tip when actually there was. We would be accepting that there was a certain relationship between Sale amount and Tip when indeed there was.
K Do freshmen spend significantly more time on social media than other class ranks? A recent study investigated the amount of time per day freshmen, sophomores, juniors, and seniors spent on social media while doing schoolwork. The students surveyed were U.S. residents from a 4-year, public, primarily residential institution. The accompanying computer output shows the mean time each cohort spent on social media and an ANOVA table. Construct a 95% confidence interval to compare the population mean time spent per day on social media between freshmen and seniors. Click the icon to view the summary statistics and ANOVA table. The 95% confidence interval is. (Round to one decimal place as needed.) View an ex NOV 9 Summary Statistics and ANOVA Table 6 n tv Mean Std. Dev. Source DF Class Error Total F6 FR 443 62.5 71.6 SS 99509 3 1562 7927979 1565 8027488 Print SO 330 56.5 68.5 MS 33170 5076 JU 383 72.0 80.9 Done 8 F 6.53 FB SE 410 50.4 62.9 P 0.000 ZA 9 F9 X k answer
Create an Excel spreadsheet. Conduct an independent sample t-test evaluating if cat owners or dog owners love their pet more. Ratings for cat owners- 7,6,5,9,5 Ratings for dog owners- 8,7,9,10 Write APA formatted results for thus analysis, including Cohen's d for the results and a bar graph with Error Bars showing 95 percent confidence intervals.
which of the following sample data: sample size= 100 sample mean= 340z/hr sample variance= 90z/ hr construct a 98% confidence interval for μ. the population mean is what?
A real estate agent wants to know if tax assessors and real estate appraisers closely agree on the values of homes. A random sample of the two independent groups evaluated 12 homes. The data is given below. Tax Assessors Real Estate Appraisers x̄1 = $102,344 x̄2 = $105,827 s1 = $3,952 s2 = $4,341 n1 = 12 n2 = 12 Construct a confidence interval for the mean difference in the home values for each group. A real estate agent wants to know if tax assessors and real estate appraisers closely agree on the values of homes. A random sample of the two independent groups evaluated 12 homes. The data is given below. Tax Assessors Real Estate Appraisers x̄1 = $102,344 x̄2 = $105,827 s1 = $3,952 s2 = $4,341 n1 = 12 n2 = 12 Construct a confidence interval for the mean difference in the home values for each group. (-6999, 33.302) (-6998, 31.516) (-8264, 1297.8) (-6804, -161.5)
In order to determine if weather conditions play a significant role in how a disease effects wheat, fields of wheat are exposed to this disease over three consecutive summers, 2002-2004. The fields are later rated on a scale of 0.0 (resistant) to 10.0 (susceptible) based on how the disease has infected the field. The results are shown below along with the ANOVA table. At the 95% confidence level, compare the mean scores across the three years. 2002 2003 2004 7 7.3 5 4.7 8 3 8 5 2 3.3 3.3 7 6.3 4.7 7.3 7 3.7 8 7 4.3 6. 7 4.3 2 6.3 6.7 ANOVA Source of Variation df MS Treatment 20.97333 2 10.48667 4.127165 Error 76.22667 30 2.540889 Total 97.2 32
4.753, 4.375, 4.177, 4.677, 4.425, 4.227, 4.122, 4.250, 3.953, 4.195, 4.293, 4.413 An 80% confidence interval for the mean rate is
Sleeping outlier: A simple random sample of ten college freshmen were asked how many hours of sleep they typically got per night. The results were 24, 8, 6.5, 6, 9, 8.5, 7.5, 6.5, 8.5, 9.5 The data contain an outlier that is clearly a mistake. Eliminate the outlier, then construct a 95% confidence interval for the mean amount of sleep from the remaining values. A 95% confidence interval for the mean amount of sleep from the remaining values is ___ < u < ___.
The customer service ratings for two banks are found below. As manager decide which bank your company should select using a 90% confidence level. Conduct a test to determine whether there is a significant difference between the variances of the two banks' rating. Current New Bank 89.9 80.4 82.2 98.7 75.1 83.1 41.7 99.8 84.3 86.2 98.6 97.1 75.4 87.9 80.6 78.5 76.4 69.9 81.4 98.5 59.7 82.9 98.4 49.5 83.4 54.6 76.2 90.1 1. Provide the null hypothesis:. a. Ho: o?, s o2, b. Họ: o?, 2 o?2 c. Ho: o?, = o?2 d. Ho: o?, * o?2 2. Compute the test statistic (Round to the second decimal place) 3. Determine the p-value (Round to the third decimal place) 4. What do you conclude 5. What would you recommend

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