Study the definition of the following two functions "Rate" and "Bonus" and answer the question below. int Rate (int one, int two) int R = one; %3D for (int i = 0; i <= two % 2; i++) R =R+ i * i; %3D return R; int Bonus (int numl, int num2) int R= Rate (numl,num2); if (numl > 20) numl- num2 10 +R; else num2 = numl *20 + R; %3D return num2 numl; What is the output of the following code segment? cout << Bonus (2, 4);
Study the definition of the following two functions "Rate" and "Bonus" and answer the question below. int Rate (int one, int two) int R = one; %3D for (int i = 0; i <= two % 2; i++) R =R+ i * i; %3D return R; int Bonus (int numl, int num2) int R= Rate (numl,num2); if (numl > 20) numl- num2 10 +R; else num2 = numl *20 + R; %3D return num2 numl; What is the output of the following code segment? cout << Bonus (2, 4);
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
![Study the definition of the following two functions "Rate" and "Bonus" and
answer the question below.
int Rate (int one, int two)
int R = one;
for (int i = 0; i <= two % 2; i++)
R =R+ i * i;
return R;
int Bonus (int numl, int num2)
int R Rate (numl, num2);
if (numl > 20)
numl num2 *
10 +R;
else
num2
num1
* 20 + R;
return num2
numl;
}
What is the output of the following code segment?
cout << Bonus (2, 4);](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F29753fbb-c19a-4e3d-a7db-88f34566db88%2Fa762678c-699d-49d7-a03b-f202507c8df6%2Ffnmpx5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Study the definition of the following two functions "Rate" and "Bonus" and
answer the question below.
int Rate (int one, int two)
int R = one;
for (int i = 0; i <= two % 2; i++)
R =R+ i * i;
return R;
int Bonus (int numl, int num2)
int R Rate (numl, num2);
if (numl > 20)
numl num2 *
10 +R;
else
num2
num1
* 20 + R;
return num2
numl;
}
What is the output of the following code segment?
cout << Bonus (2, 4);
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