study of peach trees found that the average number of peaches per tree was 525. The standard deviation of the population is 140 peaches per tree. A scientist wishes to find the 90% confidence interval for the mean number of peaches per tree. How many trees does she need to sample to obtain an average accurate to within 18 peaches per tree? b) Find tα/2 when n=25 for the 95% confidence interval for the mean. answer all parts 1a and 1b. Tha

Q: A sample of the reading scores of 40 foundatin students has a mean marks of 25. If the standard…

A:

Q: The tensile strength of paper using 5% hardwood and 10% hardwood are to be compared. A random sample…

A: Let  A: Tensile strength of paper using 5% hardwood B: Tensile strength of paper using 10% hardwood…

Q: A sociologist found that in a sample of 49 retired police officers, the average number of jobs they…

A: sample size(n)=49 Mean(x)=7.2 standard deviation(s)=2.1 confidence level=99%

Q: How large a sample should be selected to provide a 90% confidence interval with a margin of error of…

A:

Q: study of peach trees found that the average number of peaches per tree was 625. The standard…

A: Given that  Population Standard Deviation = 35

Q: A study of peach trees found that the average number of peaches per tree was 625.  The standard…

A:

Q: The heights of pine trees at a local tree farm are known to follow a normal distribution with a…

A: Given: Sample Sizen=99Sample MeanX=121Standard Deviationσ=7 The z value corresponding to the area…

Q: The mean and the standard deviation of a normal population are 11,795 and 14054 respectively. If n=…

A:

Q: The average height of students at UT from an SRS of 11 students gave a standard deviation of 3.0…

A: Givensample size(n)=11standard deviation(s)=3.0confidence level=95%

Q: A psychologist wants to estimate the variance of scores obtained by employees on a test. A random…

A: Confidence interval:A confidence interval shows the probability that a parameter will fall between a…

Q: Noise levels in a hospital were measured at 81 different locations. The average level was found to…

A: It is given that, Sample mean = 61.2 decibels. Sample standard deviation, s is 7.9 decibels. The…

Q: A 95% confidence interval for the mean was computed with a sample of size 90 to be (16,22). a. What…

A:

Q: A study was commissioned to find the mean weight of the residents in certain town. The study…

A: Given: n=58, x=174 and s=38. Now,Degrees of freedom=n-1=58-1=57 Then, at 95% confidence level, the…

Q: The capacities (in ampere-hours) were measured for a sample of 120 batteries. The average was 178…

A:

Q: . If she wants to make a 95% confidence interval for the mean with the margin of error of 5 cm, at…

A: here from given information , σ = 17 cm MOE = 5cm here Z-critical for 95 % confidence level = 1.96…

Q: The health of the bear population in Yellowstone National park is monitored by periodic measurements…

A: Given Mean = 182.9 Standard deviation=121.8 n=54

Q: A random sample of size 30 is taken from a normal distribution with standard deviation 9. The…

A: A random sample of size 30 is taken from a normal distribution with standard deviation 9. The sample…

Q: Among those taking the Graduate Record Exam, 18 people are randomly selected. This group had a mean…

A:

Q: Find the 95% confidence interval (CI) and margin of error (ME) of the true mean weights of male…

A: As the population standard deviation is unknown, the t-test statistic to be used for estimating the…

Q: Find the lower limit of 95% confidence interval. An SRS of 36 students were taken from high schools…

A: Given Mean=85 Standard deviations=7.15 n=36

Q: The 90% confidence interval for the true mean of national statistics examination scores is 81 < ? <…

A:

Q: A study found that the average time it took a person to find their dream home was 5.9 months. If a…

A: From the provided information, Sample size (n) = 36 Sample mean (x̅) = 5.9 months Population…

Q: The average GRE scores of graduated students at a particular university has an unknown mean and…

A: Given,sample size(n)=1000sample mean(x¯)=500satandard deviation(s0=50degrees of…

Q: Assume researchers are trying to find out the mean concentration levels of a specific drug in a…

A:

Q: Assume that the mean weight for American men in their twenties is 180 pounds with a standard…

A: The provided sample mean is Xˉ=175\bar X = 175 and the known population standard deviation is…

Q: A researcher wants to estimate the mean blood cholesterol level of young men ages 15-25 with a 90.1%…

A:

Q: Noise levels at various area urban hospitals were measured in decibels. The mean noise level in  69…

A: We want to find 96% CI for population mean μ

Q: Marine biologists have been studying the effects of acidification of the oceans on weights of male…

A: We have given information, The margin of error E=54 kg The standard deviation σ=122 kg The…

Q: How large of a sample is required for a to construct a 95% confidence interval around a mean with an…

A: It is given that  Standard deviation, σ = 95 Margin of error, E = 3

Q: 3. A sample of 8 adult elephants had an average weight of 12,300 pounds. The standard deviation for…

A:

Q: How large of a sample is required for a to construct a 90% confidence interval around a mean with an…

A: Given information- Population standard deviation, σ = 105 Let, Confidence interval = 0.90…

Q: 95% confidence interval of the population mean

A: Given : Sample Size, n = 40 Sample Mean, x̄ = 500 sample standard…

Q: Find a 99% confidence interval for μ.

A: The sample size is n = 7 Sample mean = 46.14 Sample SD s = 1.19 At 99% confidence level and df = (n…

Q: Karen wants to advertise how many chocolate chips are in each Big Chip cookie at her bakery. She…

A: Given mean of 5.9 standard deviation of 3.4.

Q: The average number of calories in a sample of 50 regular bagels is 405. If the standard deviation is…

A:

Q: Noise levels at various area urban hospitals were measured in decibels. The mean of the noise levels…

A: We have given that Sample size (n) = 81Sample mean (x̅) = 62.04Population Standard deviations (σ) =…

Q: A random sample of 250 students at a university finds that these students take a mean of 15 credit…

A: Solution: From the given information, the 99% confidence interval for the mean credit hours is…

Q: A survey taken several years ago found that the average time a person reading a newspaper was…

A: Given:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.