Students collect data on the force applied to a tennis ball by a tennis racquet and create the force-time graph below. What is the impulse on the tennis ball from the tennis racquet?
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Students collect data on the force applied to a tennis ball by a tennis racquet and create the force-time graph below. What is the impulse on the tennis ball from the tennis racquet?
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- The bumper of a car has a force sensor mounted inside which records the force vs time graph during crash testing. A particular collision occurs between t = 0.075s and t = 2.32s and can be modelled by the following function: F(t) = 4t4 – 80t² + 140t – 10 A graph of the collision is also provided below: Impulse 60 50 40 30 20 10 1 time (s) Part A The impulse during the collision will be while the maximum force experience by the bumper will be 75 kg · m/s, 33N 54 kg · m/s, 54N O 75 kg · m/s, 54N 54 kg · m/s, 33N (N) aɔ10A 2 kg car is traveling at 10 m/s. It collides and sitcks with a 5 kg car traveling the opposite direcyion at 7 m/s. a. Draw an IF Chart for the scenario b. Calculate the total initial momentum c. Calculate the final velocity of the two carsA 156-gram baseball is hit toward the left by a bat. The magnitude of the force the bat exerts on the ball as a function of time is shown in (Figure 1). -magnitude of impulse = 12 N*s -Magnitude of the ball's velocity when it is at rest = 77 m/s a)what is the magnitude of the ball's velocity after it is hit if it is initially moving to the right at 31 m/s b)what is the direction of this velocity?
- A 100g ball traveling horizantally at 25 m/s strikes a wall and rebounds at 19 m/s. What is the magnitude of the impulse experienced by the ball during the rebound? A. 1.2 Ns B. 1.8 Ns C. 4.4 Ns D. 5.4 Ns E. 7.2 NsE6.) A ball experiences a change in momentum of 24 kg-m/s.a. What is the impulse acting on the ball?b. If the time of interaction is 0.15 s, what is the magnitude of the average force acting on the ball? Answer with the correct formula.You drop a steel ball and a clay ball, both of the same mass, from the same distance. The steel ball strikes the ground and rebounds with almost the same speed. The clay ball strikes the ground and sticks. Assume the collisions occur over roughly the same amount of time. Which ball exerted a greater force on the ground? Select the correct answer with the best explanation. A. The two exert the same force. Since they collide with the same initial momentum, they will exert thesame force.B. The clay ball exerts the greater force. Since it starts with some momentum and ends with no momen- tum, it undergoes a greater change in momentum than the steel ball, which rebounds with the same momentum (no change).C. The clay ball exerts the greater force. All of its energy is transferred to the floor, whereas the steelball rebounds with the same kinetic energy, doing no work on the floor.D. The steel ball exerts the greater force. Since it starts with some momentum and it reverses the direction of…
- A 1500 kg car traveling to the north is slowed down uniformly from initial velocity of 20 m/s by a 6000 N braking force acting opposite the car’s motion. Use the impulse-momentum theorem to answer the following questions What is the car’s velocity after 2.00 s? How far does the car move during 2.00 s? How long does it take the car to come to a complete stop?I. Conceptual Physics. Justify your answer. 1. A 10-gram rubber ball and a 10-gram clay ball are thrown at a wall with equal initial speeds. The rubber ball bounces, the clay ball sticks. Which ball exerts a larger impulse on the wall? Justify your answer.Asteroid X, speeding at 100 m/s towards an equally massive but stationary asteroid Y, collides with a glancing blow. After collision, X is deflected 350 from its original direction while Y travels at 450 to the original direction of X. See the before & after picture of the collision below. Assuming total momentum is conserved, find the speed of each asteroid after collision. a.) V = 58.2 m/s, v = 71.8 m/s b.) v = 58.2 m/s, V = 71.8 m/s
- *Problem 3: A 1000 kg car travelling at 60 mph (26.84) impacts a brick wall. The car comes to a stop in At = 15 ms. a) What is the magnitude of the impulse (J ) applied to the car? (A: 26,800 Ns) b) What is the magnitude of the net force applied to the car during the crash? (A: 1.79x106 N) c) A person with a mass of 75 kg is strapped into the car. What is the magnitude of the impulse applied to the person? (A: 2010 Ns) d) What is the magnitude of the net force applied person during the crash? (A: 134,000 N) m e) What is the acceleration of the person during the crash in terms of g? 1g = 9.8– (A: 182g) f) How could we increase the survivability of the crash? Explain.When a truck drives into a haystack, it doesn’t get damaged. When it drives into a concrete wall, there is a lot of damage. Both cases have the same initial speed for the truck and the same final speed as well. What is the difference between these two cases? A) The initial momentum is less when it strikes the haystack.B) The impulse is less when striking the haystack C) The change in momentum is less when striking the haystackD) Force of impact is less when striking the haystack If you want to hit a volleyball without making it spin, you must apply a force A) Acting below the center of mass B) Acting above the center of massC) Acting through the center of massD) It is impossible to not make it spin