A student researcher compares the ages of cars owned by students and cars owned by faculty at a local state college. A sample of 82 cars owned by students had anaverage age of 5.57 years. A sample of 118 cars owned by faculty had an average age of 6.42 years. Assume that the population standard deviation for cars owned bystudents is 3.44 years, while the population standard deviation for cars owned by faculty is 2.12 years. Determine the 95% confidence interval for the differencebetween the true mean ages for cars owned by students and facultyStep 1 of 3: Find the point estimate for the true difference between the population means

Given For students n1=82, sample mean x̄1=5.57, standard deviations σ1=3.44 For faculty n2=118,…

Answered: student researcher compares the ages of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.17 hours, with a standard deviation of 2.45 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.44 hours, with a standard deviation of 1.71 hours. Construct and interpret a 95% confidence interval for the mean difference in leisure time between adults with no children and adults with children (u1-2) Let u, represent the mean leisure hours of adults with no children under the age of 18 and u, represent the mean leisure hours of adults with children under the age of 18. The 95% confidence interval for (H, -µ2) is the range from hours to hours. (Round to two decimal places as needed.)
A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.88 hours, with a standard deviation of 2.49 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.29 hours, with a standard deviation of 1.76 hours. Construct and interpret a 90% confidence interval for the mean difference in leisure time between adults with no children and adults with children (u, - H2). Let u, represent the mean leisure hours of adults with no children under the age of 18 and µ, represent the mean leisure hours of adults with children under the age of 18. The 90% confidence interval for (µ1 - H2) is the range from hours to hours. (Round to two decimal places as needed.)
The average monthly gas bill of a random sample of 43 residents of a city is $172 with a standard deviation of $24.5. Assume the gas bills are normally distributed. Construct a 90% confidence interval for the population mean monthly gas bills of all residents.
In a sample of 10 randomly selected black bears from northeast Pennsylvania, the sample mean was 214.1 pounds and the sample standard deviation was 51.1 pounds. Construct a 99% confidence interval estimate for the population standard deviation of all black bears in this region.
Salaries of 34 college graduates who took a statistics course in college have a mean, x, of $67,400. Assuming a standard deviation, o, of $15,845, construct a 90% confidence interval for estimating the population mean u.
A wildlife study is designed to find the mean weight of salmon caught by an Alaskan fishing company. Find the minimum sample size needed in order to construct a 95% confidence interval for the mean weight of such salmon, to within 0.30 pounds. Assume that the standard deviation of 3.10.
The Aloha Taxi Cab Company of Honolulu, Hawaii, wants to estimate the mean life of tires on its cabs. A random sample of 15 tires from the cabs are found to have a life of 18,280 miles with sample standard deviation of 1,310 miles. Find a 90% confidence interval for the mean life of all such tires on Aloha Taxi Cabs.
A sample of 12 suburban hotels showed that the mean revenue is $1117. It is known that the standard deviation is $121.8. Construct the 90% confidence interval for the true average revenue of all suburban hotels.
A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.75 hours, with a standard deviation of 2.47 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.03 hours, with a standard deviation of 1.78 hours. Construct and interpret a 95% confidence interval for the mean difference in leisure time between adults with no children and adults with children (u, - H2). Let H, represent the mean leisure hours of adults with no children under the age of 18 and u, represent the mean leisure hours of adults with children under the age of 18. The 95% confidence interval for (µ1 - H2) is the range from hours to hours. (Round to two decimal places as needed.)
After a sewer spill into a lake, an environmentalist wanted to test to see if the water was safe (mean bacteria count per unit volume of water is less than 200). Ten samples along different locations of the lake resulted in a sample mean of 192.7 and a sample standard deviation of 10.81. 2. a. Construct a 95% confidence interval for the mean.
A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.01 hours, with a standard deviation of 2.48 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.42 hours, with a standard deviation of 1.68 hours. Construct and interpret a 95 % confidence interval for the mean difference in leisure time between adults with no children and adults with children left parenthesis mu 1 minus mu 2 right parenthesis .
A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.25 hours, with a standard deviation of 2.29 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.32 hours, with a standard deviation of 1.89 hours. Construct and interpret a 95% confidence interval for the mean difference in leisure time between adults with no children and adults with children (H1 - 2) Let u, represent the mean leisure hours of adults with no children under the age of 18 and u, represent the mean leisure hours of adults with children under the age of 18. The 95% confidence interval for (H - H2) is the range from 0.00 hours to 1.86 hours. (Round to two decimal places as needed.) What is the interpretation of this confidence interval? O A. There is a 95% probability that the difference of the means is in the interval. Conclude that there is a significant difference in the number of leisure hours. O B.…

Recommended textbooks for you

MATLAB: An Introduction with Applications

Statistics

ISBN:

9781119256830

Author:

Amos Gilat

Publisher:

John Wiley & Sons Inc

Probability and Statistics for Engineering and th…

Statistics

ISBN:

9781305251809

Author:

Jay L. Devore

Publisher:

Cengage Learning

Statistics for The Behavioral Sciences (MindTap C…

Statistics

ISBN:

9781305504912

Author:

Frederick J Gravetter, Larry B. Wallnau

Publisher:

Cengage Learning

MATLAB: An Introduction with Applications

Statistics

ISBN:

9781119256830

Author:

Amos Gilat

Publisher:

John Wiley & Sons Inc

Probability and Statistics for Engineering and th…

Statistics

ISBN:

9781305251809

Author:

Jay L. Devore

Publisher:

Cengage Learning

Statistics for The Behavioral Sciences (MindTap C…

Statistics

ISBN:

9781305504912

Author:

Frederick J Gravetter, Larry B. Wallnau

Publisher:

Cengage Learning

Elementary Statistics: Picturing the World (7th E…

Statistics

ISBN:

9780134683416

Author:

Ron Larson, Betsy Farber

Publisher:

PEARSON

The Basic Practice of Statistics

Statistics

ISBN:

9781319042578

Author:

David S. Moore, William I. Notz, Michael A. Fligner

Publisher:

W. H. Freeman

Introduction to the Practice of Statistics

Statistics

ISBN:

9781319013387

Author:

David S. Moore, George P. McCabe, Bruce A. Craig

Publisher:

W. H. Freeman

SEE MORE TEXTBOOKS