Structure and Function of DNA and RNA
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![Structure and Function of DNA and RNA
Q2.1- Hydrogen bonds can form with bases on the opposite DNA strands
in the double helix, or between the bases and H2O in the single stranded
conformation. Considering that the double helix is the most stable
conformation in water, how does this observation support the conclusion
that base stacking contributes more to helix stability than interbase
hydrogen bonding?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1da2b7e6-ff1f-4d03-afb3-6b710fedc971%2F2d40f9f3-239e-4bd5-9d34-b6431fe5aee3%2F219ye5h_processed.jpeg&w=3840&q=75)
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- STRUCTURE OF DNA Ueing the complementary base pairing rules in DNA, complete the following base pairs: Adenine - Cytosine -i Guanine -i Thymine - : Adenine : Cytosine :: Guanine :: Thymine 1The Basic Structure of DNA 1. Nucleotides are the monomer subunits of DNA polymers. Review the structure of a nucleotide by labeling the three main parts: the sugar, the phosphate group and the nitrogenous base of the one shown below. NH2 N- || ОН 2. Which part (sugar, phosphate, or nitrogenous base) of the four types of nucleotides differ? 3. Based on the complementary base pairing rules we know that: A(denosine) pairs with and that G(uanine) pairs with 4. What two types of bonds are found in a DNA molecule and where are they found? а. bonds are found b. bonds are found O=a-opppApCpCpUpApGpApU-OH(a) Using the straight-chain sugar convention, write the structure of the DNA strand that encoded this short stretch of RNA.(b) Using the simplest convention for representing the DNA base sequence, write the structure of the nontemplate DNA strand.
- Composition as a mole fraction of one of a double-stranded DNA strand T = 0.22 and C = 0.30. In the light of this information, the following values are Calculate as a fraction. If the given information is used to calculate the desired value, If it is not sufficient, indicate the result as X.need help finding what the name and what the letters areBiological Macromolecules Understanding that DNA replication is semiconservative -pil... 0/5 Julianna The coding (sense) strands of two complete (double-stranded) DNA molecules have the base sequences shown in the table below. Two replication experiments are done with each molecule: 1. In Experiment #1, samples of each DNA molecule are incubated with radioactive adenine, along with appropriate replication enzymes, ATP, adenine, thymine, and cytosine. Experiment #1 is stopped when each DNA molecule has replicated once. 2. In Experiment # 2, all the DNA molecules from #1 are purified, and then incubated with with a similar reaction mixture is used this time. Experiment #2 is stopped when each DNA molecule has replicated one more time. - ? except non-radioactive adenine olo Predict the percentage of DNA in each sample that is radioactive after each experiment. Round your answers to the nearest percent. DNA coding strand sequence 5'- TGGCTG-3' 5'- ACGGGC-3' % of DNA radioactive after...…
- Number of Okazaki Fragments in E. coli and Human DNA Replication Approximately how many Okazaki fragments are synthesized in the course of replicating an E. coli chromosome? How many in replicating an “average� human chromosome?Codon-Anticodon Recognition: Base-Pairing Possibilities (Integrates with Chapter 11.) Draw base-pair structures for (a) a G:C base pair. (b) a C:G base pair. (C) a G:U base pair, and (d) a U:G base pair. Note how these various base pairs differ in the potential hydrogen-bonding patterns they present within the major groove and minor groove of a double-helical nucleic acid.Helicase Unwinding of the E. coli Chromosome Hexameric helicases, such as DnaB, the MCM proteins, and papilloma virus El helicase (illustrated in Figures 16.22 to 16.25), unwind DNA by passing one strand of the DNA duplex through the central pore, using a mechanism based on ATP-dependent binding interactions with the bases of that strand. The genome of E. coli K12 consists of 4,686,137 nucleotides. Assuming that DnaB functions like papilloma virus El helicase, from the information given in Chapter 16 on ATP-coupled DNA unwinding, calculate how many molecules of ATP would be needed to completely unwind the E. coli K 12 chromosome.
- Determining the amino acid sequence in a protein usually in- volves treating the protein with various reagents that break up the protein into smaller fragments that can be individually sequenced. Treating a particular 11-amino acid polypeptide with one reagent produced the fragments: Ala-Leu-Phe-Gly-Asn-Lys Trp-Glu-Cys Gly-Arg Treating the same polypeptide with a different reagent pro- duced the fragments: Glu-Cys Gly-Asn-Lys-Trp Gly-Arg-Ala-Leu-Phe What is the amino acid sequence of the polypeptide?Not sure if correct1
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