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Structural Engineers in an iron manufacturing company describe the results of deformation on the natural frequency of alloys made from composite material. Five such delaminated alloys were subjected to loads, and the resulting frequencies (in hertz) were as follows: 230.66, 233.05, 232.58, 229.48, 232.58 Compute a 90% prediction interval on the diameter of the natural frequency of the next beam of this type that will be tested. a. 228.1 Sxn+1S235.2

Structural Engineers in an iron manufacturing company describe the results of deformation on the natural frequency of alloys made from composite material. Five such delaminated alloys were subjected to loads, and the resulting frequencies (in hertz) were as follows: 230.66, 233.05, 232.58, 229.48, 232.58 Compute a 90% prediction interval on the diameter of the natural frequency of the next beam of this type that will be tested. a. 228.1 Sxn+1S235.2

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Structural Engineers in an iron manufacturing company describe the results of deformation on the natural frequency of alloys made from composite material. Five such delaminated alloys were subjected to loads, and the resulting frequencies (in hertz) were as follows: 230.66, 233.05, 232.58, 229.48, 232.58 Compute a 90% prediction interval on the diameter of the natural frequency of the next beam of this type that will be tested. Da.228.1 <xn+1<235.2 b. None of the above Oc. 230.2 su< 233.1 O d. The 90% prediction interval is wider than the 90% confidence interval on the population mean
Transcribed Image Text:Structural Engineers in an iron manufacturing company describe the results of deformation on the natural frequency of alloys made from composite material. Five such delaminated alloys were subjected to loads, and the resulting frequencies (in hertz) were as follows: 230.66, 233.05, 232.58, 229.48, 232.58 Compute a 90% prediction interval on the diameter of the natural frequency of the next beam of this type that will be tested. Da.228.1 <xn+1<235.2 b. None of the above Oc. 230.2 su< 233.1 O d. The 90% prediction interval is wider than the 90% confidence interval on the population mean
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