Strontium 90 (half-life 5 29 y) is one of the worst components of fullout from atmospheric testing of nuclear bombs because it concentrates in the bones.The last such bombs was tested in 1963.In the year 2021,how many half lifes will have gone by for the strontium 90 produced in the blast, what fraction of the strontium 90 will remain in that year.
Strontium 90 (half-life 5 29 y) is one of the worst components of fullout from atmospheric testing of nuclear bombs because it concentrates in the bones.The last such bombs was tested in 1963.In the year 2021,how many half lifes will have gone by for the strontium 90 produced in the blast, what fraction of the strontium 90 will remain in that year.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Strontium 90 (half-life 5 29 y) is one of the worst components of fullout from atmospheric testing of nuclear bombs because it concentrates in the bones.The last such bombs was tested in 1963.In the year 2021,how many half lifes will have gone by for the strontium 90 produced in the blast, what fraction of the strontium 90 will remain in that year.

Transcribed Image Text:have passed).
N. second
half-life
first
N.
third
N.
half-life
2
half-life
8
Thus, three half-lives have passed, and with No/8 remaining, the final amount of iodine-131 is 18
of 40 mg, or 5 mg.
14
EXAMPLE1.4 Finding the Elapsed Time
How long would it take a sample of 1"C to decay to one-fourth of its original activity?
The half-life of"C is 5730 y.
Solution
The "C will decay for a time period equal to two half-lives, as shown by the number of
arrows in the sequence
N.
To find the elapsed time, multiply the number of half-lives by the half-life.
(2 half-livesX5730 y/half-life) = 11,460 y
Confidence Exercise!
Let's test your understanding
Please cut this portion!
I. Finding the Number of Half-Lives and the Final Amount
1. Strontium-90 (half-life 5 29 y) is one of the worst components of fallout from atmospheric
testing of nuclear bombs because it concentrates in the bones. The last such bomb was
tested in 1963. In the year 2021, how many half-ives will have gone by for the strontium-90
produced in the blast? What fraction of the strontium-90 will remain in that year?
II. Finding the Elapsed Time
2. Technetium-99 is often used as a radioactive tracer to assess heart
half-life is 6.0 h. How long would it take a sample of technetium-99 to decay to one
sixteenth of its original amount?
amage. Its
15
Carbon-14 Dating
Carbon-14 dating is used on materials that were once part of living things,
Such as wood, bone, and parchment. The process depends on the fact that living things
(including you) contain a known amount of radioactive 14C, which has a half-ife of 5730
years.
The 14C nuclei exist in living things because the isotope is continually being
produced in the atmosphere by cosmic rays. Cosmic rays are high-speed charged
particles that reach the Earth from various sources, ike the Sun. The "rays" are primarily
protons, and on entering the upper atmosphere, they can cause reactions that produce
neutrons (• Fig. 10.10). These neutrons react with the nuclei of nitrogen atoms in the
atmosphere to produce 14C and a proton (11H):
Radioactive dating can be done by analyzing the fraction of carbon in organic material
that is carbon-14.
II
Page14
Page13

Transcribed Image Text:Neutron
in
In addition to alpha, beta, and gamma radiation, certain nuclear processes
(generally involving artificial radioisotopes) emit positrons fe. For example,
12
Confidence Exercise!
Let's test your understanding
Please cut this portion!
Direction: Complete the following equations for nuclear decay, and state whether each process is
alpha decay, beta decay, or gamma decay.
1. Sc → Sc +
2. 2Th - + He
3. sc - Ti + -
4. B -
+ -fe
5. 210Po - 20Pb +
6. 207PO → 20Po +
7. Write the equation for each of the following.
a. alpha decay of 226Ra
b. beta decay of Co
13
Half-Life and Rate of Decay
The rate of decay of a given radioisotope is described by the term half-ife,
which is the time it takes for half of the nuclei of a given radioactive sample to decay. Ih other
words, after one half-ife has gone by, one-half of the original amount of isotope remains
undecayed; after two half-ives (1/2 x ½ ) = one- fourth (1/4) of the original amount is
undecayed; and so on (• Fig. 4.)
(200 decays/s)
II
Page 12
Page11
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