String dataString is read from input. If dataString does not contain character 'n', then output "Character 'n' is not found." Otherwise, output: • "Last occurrence of character 'n' is at index" • the index of the last occurrence of 'n' in dataString
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I need help with this java code: More string operations.
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- String orig_string is read from input. Assign variable sliced_saying with all the characters in orig_string, except for the last character.Part 2: Forms often allow a user to enter an integer. Write a program that takes in a string representing an integer as input, and outputs yes if every character is a digit 0-9. Ex: If the input is 1995, the output is: yes Ex: If the input is 42,000 or 1995!, the output is: no Hint: Use a loop and the isdigit() function (don't forget to include the cctype library). Do not use break! please do it in c++3. Complete the function count_digits. This function takes one parameter - a string (s). It should return the number of digits in s. For example, if s is "25 or 6 to 4 is a song by Chicago" then count_digits should return 4. count_digits should not print the result- it should return it. Do not change anything outside count_digits. Save & Run Load History Show CodeLens 1 def count_digits(s): 2 ''Returns the number of digits in s''" 3 pass #Hint: make a string of digits to use #in checking whether each character #is a digit. And use the accumulator #pattern 4 6. 7 8. 9 user_string 10 num_digits 11 print("There are", num_digits, "digits in", user_string) input("Please enter a string: ") count_digits(user_string) 12
- Given string userString on one line, character newChar on a second line, and integer strIndex on a third line, change the character at index strIndex of userString to newChar. Ex: If the input is: garlic Z 0 then the output is: Zarlic Note: Assume the length of string userString is greater than strIndex. #include <iostream> #include <string> using namespace std; int main() { string userString; char newChar; int strIndex; getline(cin, userString); cin >> newChar; cin >> strIndex; /* Your code goes here */ cout << userString << endl; return 0; }String user_input is read from input. If user_input starts with 'G', then output 'String starts with G'. Otherwise, if all the characters in user_input are numbers, then output 'All numbers'. If none of the above are true, output 'No condition fits'.Usage: mortgagepmt [-s] -r rate [-d downpayment] price In this assignment, you are asked to do a mortgage payment calculation. All information needed for this will be passed to the program on the command line. There will be no user input during the execution of the program. You will need a few pieces of information. The price of the home and the amount of the down payment. You will also need to know the interest rate and the term of the mortgage. To figure your mortgage payment, start by converting your annual interest rate to a monthly interest rate by dividing by 12. Next, add 1 to the monthly rate. Third, multiply the number of years in the term of the mortgage by 12 to calculate the number of monthly payments you’ll make. Fourth, raise the result of 1 plus the monthly rate to the negative power of the number of monthly payments you’ll make. Fifth, subtract that result from 1. Sixth, divide the monthly rate by the result. Last, multiply the result by the amount you want to borrow.…
- get_nth_word_from_string(s, n): This function takes a string s and a non-negative integer n as input. The string s may contain substrings of text separated by commas. The function should return the n’th comma-separated substring. We will start counting at 0, so if n=0, then the first substring should be returned (i.e., everything before the first comma, if there is such a comma); if n=1, then the second substring should be returned (i.e., everything between the first comma and second comma, if there is such a comma); and so on. If there is no n’th substring in s, then the empty string should be returned. Note: You may use the string count method in this function. Note: If a space follows a comma, do not include the space as part of the substring to be returned.get_nth_word_from_string(s, n): This function takes a string s and a non-negative integer n as input. The string s may contain substrings of text separated by commas. The function should return the n’th comma-separated substring. We will start counting at 0, so if n=0, then the first substring should be returned (i.e., everything before the first comma, if there is such a comma); if n=1, then the second substring should be returned (i.e., everything between the first comma and second comma, if there is such a comma); and so on. If there is no n’th substring in s, then the empty string should be returned. Note: You may use the string count method in this function. Note: If a space follows a comma, do not include the space as part of the substring to be returned. >>> get_nth_word_from_string("dreary, pondered, weak, weary", 0) 'dreary'String orig_string is read from input. Assign variable sliced_string with the orig_string slice that excludes the characters at indices 10 and 11.
- Dec2Hex function : def dec_to_hex(decimal): hex_digits = "0123456789ABCDEF" hex_string = "" while decimal > 0: hex_digit = decimal % 16 hex_string = hex_digits[hex_digit] + hex_string decimal = decimal // 16 # Pad the hexadecimal string with zeroes to make it a multiple of 2 bytes hex_string = hex_string.rjust((len(hex_string) + 1) // 2 * 2, "0") # Convert the hexadecimal string to bytes hex_bytes = bytes.fromhex(hex_string) return hex_bytes Add unit-testing code to your Dec2Hex exercise, and then perform aUnit test of the updated Dec2Hex code. Perform a Profile of your Dec2Hex function. Write a function that takes a timedate object as a parameter andcalculates the number of years from NOW to the time in the timedateobject.Create aC++ function named countWords that counts the number of words in the current string and displays a message stating how many words are in the string Examples: The string 2015 has zero words The string "Hello World" has two words The string " I am Woman " has 3 wordsThis application accepts an arbitrary number of user inputs. Every time this application receives a string, it should add the string to a growing string.Newly added strings should be added to the growing string at the index equal to the newly added string's length.