answer all please, thanks! A certain story, describing several weeks of a long war, includes many details of injuries and outcomes. The accompanying table summarizes 147 recorded injuries for which both injury site and outcome are provided inthe story. Are some kinds of injuries more lethal than others? Complete parts a through e below.Click the icon to view the table.O D. Ho: Site of injury and whether or not it was lethal are not indeHA: Site of injury and whether or not it was lethal are indepenTable of injuriesFind the expected values under the null hypothesis.Lethal?Lethal?FatalNot fatalTotalFatalNot fatalBody59867Body52.8714.13Injury Site Head/neck47350Injury SiteHead/neck39.4610.54Limb102030Total11631147Limb23.676.32(Round to two decimal places as needed.)b) Compute the x statistic.Done(Round to two decimal places as needed.)c) How many degrees of freedom does the x statistic have? c) How many degrees of freedom does the x statistic have?2(Type a whole number.)d) Find the P-value.P-value = 0.000(Round to three decimal places as needed.)e) What should be concluded?Rejectthe null hypothesis for a = 0.05 andconcludethat site of injury and whether or not it was lethal are not independent.

a) Ho: site of injury and whether or not it was the is not independent Ha: site of injury and whether or not it was the is not independent. By applying the Chi-square test of independence, Observed (O) frequency table: Expected frequencies and Test statistics can be calculated as follow:Expected frequency = (row total*column total)/Grand total b)Chi-square test statistic (χ²) : Chi-square test statistic (χ²) = Σ(O-E)2/E = 47.62 Degree of freedom = (row-1)*(column - 1) = (3-1)*(2*1) = 2*1 = 2 significance level α = 0.05 The test statistic follows the χ²-distribution with 2 degrees of freedom. P-value = 0.00001 Since the P-value < significance level α, reject the null hypothesis. Reject the null hypothesis for α = 0.05 and conclude that site of injury and whether or not it was the is not independent.