Stop to Think 10.11: Pz > Pg = Pc > Pp. The power here is the rate at which each runner's internal chemical energy is converted into gravitational potential energy. The change in gravitational potential energy is mgAy, so the power is mgAy/At. For runner A, the ratio mAy/At equals (80 kg)(10 m)/(10 s) = 80 kg•m/s. For C, the ratio is also 80 kg • m/s. For B, it's 100 kg•m/s, while for D the ratio is 64 kg •m/s.

icon
Related questions
Question
100%
Stop to Think 10.11: Pg > PĄ = Pc > P. The power here is the
rate at which each runner's internal chemical energy is converted
into gravitational potential energy. The change in gravitational
potential energy is mgAy, so the power is mgAy/At. For runner A,
the ratio mAy/At equals (80 kg)(10 m)/(10 s) = 80 kg • m/s. For
C, the ratio is also 80 kg • m/s. For B, it's 100 kg • m/s, while for D
the ratio is 64 kg• m/s.
Transcribed Image Text:Stop to Think 10.11: Pg > PĄ = Pc > P. The power here is the rate at which each runner's internal chemical energy is converted into gravitational potential energy. The change in gravitational potential energy is mgAy, so the power is mgAy/At. For runner A, the ratio mAy/At equals (80 kg)(10 m)/(10 s) = 80 kg • m/s. For C, the ratio is also 80 kg • m/s. For B, it's 100 kg • m/s, while for D the ratio is 64 kg• m/s.
For Stop To Think 10.11, what is the output power for student D climbing stairs, in Watts? Use g = 10 m/s.
Transcribed Image Text:For Stop To Think 10.11, what is the output power for student D climbing stairs, in Watts? Use g = 10 m/s.
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

Blurred answer