stone is thrown near the surface of a planet and its horizontal and vertical position a function of time are given as x(t) = 5 + 8t (horizontal) y(t) = 3+ 12t -8t (vertical) here x and y are given in meters and t is in seconds. a) Calculate the magnitude of surface gravitational acceleration of this planet in units of m/s. by Calculate the time when the stone is at its maximum height. Calculate the velocity vector at t-1.125s. Calculate the velocity vector when horizontal position of the stone d) is 9m.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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Problems:
1. A stone is thrown near the surface of a planet and its horizontal and vertical position
as a function of time are given as
x(t) = 5+8t (horizontal)
y(t) = 3+ 12t – 8t2 (vertical)
where x and y are given in meters and t is in seconds.
Calculate the magnitude of surface gravitational acceleration of this
planet in units of m/s.
Calculate the time when the stone is at its maximum height.
Calculate the velocity vector at t=1.125s.
Calculate the velocity vector when horizontal position of the stone
d)
is 9m.
Transcribed Image Text:Problems: 1. A stone is thrown near the surface of a planet and its horizontal and vertical position as a function of time are given as x(t) = 5+8t (horizontal) y(t) = 3+ 12t – 8t2 (vertical) where x and y are given in meters and t is in seconds. Calculate the magnitude of surface gravitational acceleration of this planet in units of m/s. Calculate the time when the stone is at its maximum height. Calculate the velocity vector at t=1.125s. Calculate the velocity vector when horizontal position of the stone d) is 9m.
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